Answer: -4
The formula for slope is rise/run. This means that between two points, you have to see the distance going up and down/ left and right.
Looking at points (0,-1) and (3,-1), you can see that the height difference is 4 units. This means that the rise is 4.
rise/run
4/run
Left and right, the difference is only one unit.
4/run
4/1
4
This graph is also negative, so let’s add that in.
-4
This is your answer! I know it wasn’t one of the options you provided, but I’m pretty sure that this is the answer.
Hope this helps comment below for more questions :)
At the start, the tank contains
(0.02 g/L) * (1000 L) = 20 g
of chlorine. Let <em>c</em> (<em>t</em> ) denote the amount of chlorine (in grams) in the tank at time <em>t </em>.
Pure water is pumped into the tank, so no chlorine is flowing into it, but is flowing out at a rate of
(<em>c</em> (<em>t</em> )/(1000 + (10 - 25)<em>t</em> ) g/L) * (25 L/s) = 5<em>c</em> (<em>t</em> ) /(200 - 3<em>t</em> ) g/s
In case it's unclear why this is the case:
The amount of liquid in the tank at the start is 1000 L. If water is pumped in at a rate of 10 L/s, then after <em>t</em> s there will be (1000 + 10<em>t</em> ) L of liquid in the tank. But we're also removing 25 L from the tank per second, so there is a net "gain" of 10 - 25 = -15 L of liquid each second. So the volume of liquid in the tank at time <em>t</em> is (1000 - 15<em>t </em>) L. Then the concentration of chlorine per unit volume is <em>c</em> (<em>t</em> ) divided by this volume.
So the amount of chlorine in the tank changes according to

which is a linear equation. Move the non-derivative term to the left, then multiply both sides by the integrating factor 1/(200 - 5<em>t</em> )^(5/3), then integrate both sides to solve for <em>c</em> (<em>t</em> ):


![\dfrac{\mathrm d}{\mathrm dt}\left[\dfrac{c(t)}{(200-3t)^{5/3}}\right]=0](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dt%7D%5Cleft%5B%5Cdfrac%7Bc%28t%29%7D%7B%28200-3t%29%5E%7B5%2F3%7D%7D%5Cright%5D%3D0)


There are 20 g of chlorine at the start, so <em>c</em> (0) = 20. Use this to solve for <em>C</em> :

![\implies\boxed{c(t)=\dfrac1{200}\sqrt[3]{\dfrac{(200-3t)^5}5}}](https://tex.z-dn.net/?f=%5Cimplies%5Cboxed%7Bc%28t%29%3D%5Cdfrac1%7B200%7D%5Csqrt%5B3%5D%7B%5Cdfrac%7B%28200-3t%29%5E5%7D5%7D%7D)
The function of the polynomial is (b) 
From the graph, we have the following highlights
- The graph crosses the x-axis at x = -1 and x = 3
- The graph touches the x-axis at x = -2
The above highlights mean that:
- The function has a multiplicity of 1 at x = -1 and x = 3
- The function has a multiplicity of 2 at x = -2
So, the function of the polynomial is:

Assume a = 1.
So, we have:

Multiply

Hence, the function of the polynomial is (b) 
Read more about polynomial graphs at:
brainly.com/question/8878887
Answer:
x= -6
Step-by-step explanation:
Answer:
5
Step-by-step explanation:
.05 ×100=5 per cent
a nickel is 5 cent