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romanna [79]
3 years ago
13

Its a fan favorite yall know it yall love it its time to play......

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
4 0

Answer:

guessing its Still Runnin

Step-by-step explanation:

You might be interested in
Ex 65 : Étagères , merci d’ avance
Alchen [17]

Answer:

Voir ci-dessous.

Step-by-step explanation:

1.

OA/OD = 36/64 = 9/16

OB/OC = 27/48 = 9/16

m<AOB = m<COD

triangle AOB ~ trianlge DOC

m<BAO = m<CDO

AB || CD

2.

AB/CD = OA/OD

AB/80 = 36/64

AB/80 = 9/16

16AB = 9 × 80

AB = 9 × 5

AB = 45

AB = 45 cm

3.

AB = 45

BC = OC + OB = 48 + 27 = 75

AB² + AC² = BC²

45² + AC² = 75²

AC² = 5625 - 2025

AC = √3600

AC = 60 cm

hauteur = 5 × 2 cm + 4 × 60 cm

hauteur = 10 cm + 240 cm

hauteur = 250 cm

6 0
2 years ago
Please help and show the steps thank you!!
Setler [38]

Answer:

The answer to your question is  h (g(n)) = 3n² - 12n + 1

Step-by-step explanation:

                           h(n) = 3n + 1

                          g(n) = n² - 4n

Find (hg)(n)

                    h(g(n)) = 3( n² - 4n) + 1          substitution

                   h (g(n)) = 3n² - 12n + 1           expand

                 

4 0
3 years ago
Find the measure of the missing angle using the exterior angle sum theorm.
Aleks [24]

Answer:

25^{\circ}

Step-by-step explanation:

The sum of the interior angles of a triangle is equal to 180 degrees, and each side of a straight line is equal to 180 degrees. Therefore, the exterior angle labelled 150^{\circ} must be equal to the sum of the two angles marked 125^{\circ} and ?^{\circ}:

125+x=150,\\x=150-125=\boxed{25^{\circ}}

Thus, the missing angle is 25^{\circ}.

7 0
3 years ago
Another help!!! Good points fake response =report
Alex777 [14]
<h3><em><u>1</u></em><em><u>3</u></em><em><u>5</u></em><em><u>.</u></em></h3>

Step-by-step explanation:

<em>3</em><em>³</em><em>.</em><em> </em><em>(</em><em>1</em><em>2</em><em> </em><em>-</em><em> </em><em>2</em><em>÷</em><em>)</em>

<em>↓</em>

<em>Calculate</em><em> </em><em>the </em><em>sum </em><em>of </em><em>difference</em>

<em>↓</em>

<em>3</em><em>³</em><em> </em><em>×</em><em> </em><em>1</em><em>0</em><em> </em><em>÷</em><em> </em><em>2</em>

<em>↓</em><em> </em>

<em>Calculate</em><em> the</em><em> </em><em>power</em>

<em>↓</em>

<em>2</em><em>7</em><em> </em><em>×</em><em> </em><em>1</em><em>0</em><em> </em><em>÷</em><em> </em><em>2</em>

<em>CHECK✓</em><em> </em><u>135</u><u>.</u>

<u>(</u><u>Confirmation</u><u> </u><u>Answer:</u><u>1</u><u>3</u><u>5</u><u> </u><u>✓</u><u> </u><u>)</u>

<u>Alternative</u><u> </u><u>Forms </u><u>:</u>

<u>1</u><u>.</u><u>3</u><u>5</u><u> </u><u>×</u><u> </u><u>1</u><u>0</u><u>²</u>

<em>Hoping </em><em>this </em><em>helps </em><em>u,</em><em> </em><em>Have </em><em>a </em><em>great </em><em>day!</em><em>:</em><em>)</em>

<em><u>#Bra</u></em><em><u>i</u></em><em><u>nlyeveryday>^_^<</u></em>

3 0
2 years ago
Read 2 more answers
5.<br> Factorise each of the following.<br> (a)-15ab-6ab² <br> (b) 6x(2y-5)-3(5-2y)
Kobotan [32]
(a).
-15ab-6ab^2
= -(15ab+6ab^2)
= -ab(15+6b)
= -3ab(5+2b)

(b).
6x(2y-5)-3(5-2y)
= 6x(2y-5)+3(2y-5)
= (6x+3)(2y-5)
= 3(2x+1)(2y-5)

Tip: If you want to check your answer for (a), you can always simplify it back and see whether it is same as the question.

Hope this helps : )
7 0
2 years ago
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