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3 years ago

The length of a rectangle is 13 feet. The width is 9 feet. What is the perimeter of the rectangle?

Mathematics

2 answers:

KatRina [158]3 years ago

7 0

13 + 13 + 9 + 9 = 44 feet.
Please make this answer the brainliest!

Sav [38]3 years ago

7 0

Here L = 13 ft and W = 9 ft.

P = Perimeter = 2L + 2W.

Then P = 2(13 ft) + 2(9 ft) = 26 ft + 18 ft = 44 ft (answer)

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Is my answer actually incorrect and if so how?

mr Goodwill [35]

Answer:

B. 0.159

A = taking history class

B= taking sociology class

P(A) = 0.051

P(B) = 0.32

A ÷ B = $\frac{0.051}{0.32}$

= 0.159 Rounded the the nearest hundredth

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3 years ago

How to do this question

Bas_tet [7]

Answer:

Step-by-step explanation:

factor out both equations and then cancel any of the common factors. You should be left with 4x/4, which simplified is x

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2 years ago

Someone explain it please

Alina [70]

9514 1404 393

Answer:

∠A = 44°

Step-by-step explanation:

In order to find the measure of angle A, you need to know the value of the variable x. This means you need some relation that you can solve to find x.

Happily, that relation is "the sum of angles in a triangle is 180°." This means ...

84° +(x +59)° +(x +51)° = 180°

(2x + 194)° = 180° . . . collect terms

2x = -14 . . . . . . . . . . divide by °, and subtract 194

x = -7 . . . . . . . . . . . .divide by 2

Now, the measure of angle A is ...

∠A = (x +51)° = (-7 +51)°

∠A = 44°

4 0

3 years ago

elaina wrote two correct variable expressions to represent the phrase “one-fourth of a number.” which variable expressions could

antiseptic1488 [7]

One-fourth of a number

1/4n and n/4

5 0

3 years ago

Read 2 more answers

Suppose that at a state college, a random sample of 41 students is drawn, and each of the 41 students in the sample is asked to

ra1l [238]

Answer:

The confidence interval for 90% confidence would be narrower than the 95% confidence

Step-by-step explanation:

From the question we are told that

The sample size is n = 41

For a 95% confidence the level of significance is $\alpha = [100 - 95]\% = 0.05$ and

the critical value of $\frac{\alpha }{2}$ is $Z_{\frac{\alpha }{2} } =Z_{\frac{0.05 }{2} }= 1.96$

For a 90% confidence the level of significance is $\alpha = [100 - 90]\% = 0.10$ and

the critical value of $\frac{\alpha }{2}$ is $Z_{\frac{\alpha }{2} } =Z_{\frac{0.10 }{2} }= 1.645$

So we see with decreasing confidence level the critical value decrease

Now the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{s}{\sqrt{n} }$

given that other values are constant and only $Z_{\frac{\alpha }{2} }$ is varying we have that

$E\ \ \alpha \ \ Z_{\frac{\alpha }{2} }$

Hence for reducing confidence level the margin of error will be reducing

The confidence interval is mathematically represented as

$\= x - E < \mu < \= x + E$

Now looking at the above formula and information that we have deduced so far we can infer that as the confidence level reduces , the critical value reduces, the margin of error reduces and the confidence interval becomes narrower

3 0

3 years ago