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Olenka [21]
3 years ago
14

The length of a rectangle is 13 feet. The width is 9 feet. What is the perimeter of the rectangle?

Mathematics
2 answers:
KatRina [158]3 years ago
7 0
13 + 13 + 9 + 9 = 44 feet.
Please make this answer the brainliest!
Sav [38]3 years ago
7 0
Here L = 13 ft and W = 9 ft.

P = Perimeter = 2L + 2W.

Then P = 2(13 ft) + 2(9 ft) = 26 ft + 18 ft = 44 ft (answer)
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Is my answer actually incorrect and if so how?
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Answer:

B. 0.159

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P(B) = 0.32

A ÷ B = \frac{0.051}{0.32}

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5 0
3 years ago
How to do this question
Bas_tet [7]

Answer:

x

Step-by-step explanation:

factor out both equations and then cancel any of the common factors. You should be left with 4x/4, which simplified is x

7 0
2 years ago
Someone explain it please
Alina [70]

9514 1404 393

Answer:

  ∠A = 44°

Step-by-step explanation:

In order to find the measure of angle A, you need to know the value of the variable x. This means you need some relation that you can solve to find x.

Happily, that relation is "the sum of angles in a triangle is 180°." This means ...

  84° +(x +59)° +(x +51)° = 180°

  (2x + 194)° = 180° . . . collect terms

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4 0
3 years ago
elaina wrote two correct variable expressions to represent the phrase “one-fourth of a number.” which variable expressions could
antiseptic1488 [7]
One-fourth of a number

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5 0
3 years ago
Read 2 more answers
Suppose that at a state college, a random sample of 41 students is drawn, and each of the 41 students in the sample is asked to
ra1l [238]

Answer:

The  confidence interval for 90% confidence would be narrower than the 95% confidence

Step-by-step explanation:

From the question we are told that

  The  sample size is n = 41

   

For a 95% confidence the level of significance is  \alpha  = [100 - 95]\% =  0.05 and

the critical value  of  \frac{\alpha }{2}  is   Z_{\frac{\alpha }{2} } =Z_{\frac{0.05 }{2} }=  1.96

For a 90% confidence the level of significance is  \alpha  = [100 - 90]\% =  0.10 and

the critical value  of  \frac{\alpha }{2}  is   Z_{\frac{\alpha }{2} } =Z_{\frac{0.10 }{2} }=  1.645

So we see with decreasing confidence level the critical value  decrease

Now the margin of error is mathematically represented as

         E =  Z_{\frac{\alpha }{2} } *  \frac{s}{\sqrt{n} }

given that other values are constant and only Z_{\frac{\alpha }{2} } is varying we have that

         E\ \  \alpha \ \   Z_{\frac{\alpha }{2} }

Hence for  reducing confidence level the margin of error will be reducing

  The  confidence interval is mathematically represented as

        \= x  - E  <  \mu <  \= x  + E

Now looking at the above formula and information that we have deduced so far we can infer that as the confidence level reduces , the critical value  reduces, the margin of error  reduces and the confidence interval becomes narrower

3 0
3 years ago
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