The second one is correct. 66/300 = x/100
Answer:
The 95% confidence interval for the true proportion of all medical students who plan to work in a rural community is (0.0525, 0.1075).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of
.
For this problem, we have that:

95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:
The upper limit of this interval is:
The 95% confidence interval for the true proportion of all medical students who plan to work in a rural community is (0.0525, 0.1075).
Answer:
{x,y} = {8,3}
Step-by-step explanation:
// Solve equation [2] for the variable y
[2] 4y = 2x - 4
[2] y = x/2 - 1
// Plug this in for variable y in equation [1]
[1] 3x - 4•(x /2-1) = 12
[1] x = 8
// Solve equation [1] for the variable x
[1] x = 8
// By now we know this much :
x = 8
y = x/2-1
// Use the x value to solve for y
y = (/2)(8)-1 = 3
Answer:
(-4,-8)
Step-by-step explanation: