What is the slope of (-17,-11), (10,8)

Mathematics

2 answers:

poizon [28]4 years ago

6 0

-11-8=-19
-17-10=-27

slope=19/27

aalyn [17]4 years ago

4 0

Om you get the slope by putting the points in the equation y2 - y1/ x2 - x1

ok when you plug them in it should look like this

8 + 11/ 10 + 17

19/27

that would be you rnaswer becuase it can't be simplified no more hope this helped

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Allisa [31]

Answer:

its 9 x 56 then 13 x 16

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Find dy/dx and d2y/dx2. x = cos(2t), y = cos(t), 0 < t < π

pogonyaev

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\frac{\mathrm dy}{\mathrm dt}}{\frac{\mathrm dx}{\mathrm dt}}$

$y=\cos t\implies\dfrac{\mathrm dy}{\mathrm dt}=-\sin t$
$x=\cos2t\implies\dfrac{\mathrm dx}{\mathrm dt}=-2\sin2t=-4\sin t\cos t$
$\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{-\sin t}{-4\sin t\cos t}=\dfrac14\sec t$

Let $z=\dfrac{\mathrm dy}{\mathrm dx}$ . Then

$\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm dz}{\mathrm dx}=\dfrac{\mathrm dz}{\mathrm dt}\dfrac{\mathrm dt}{\mathrm dx}=\dfrac{\frac{\mathrm dz}{\mathrm dt}}{\frac{\mathrm dx}{\mathrm dt}}$
$\implies\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\frac{\mathrm d}{\mathrm dt}\left[\frac14\sec t\right]}{-4\sin t\cos t}=\dfrac{\frac14\sec t\tan t}{-4\sin t\cos t}=-\dfrac1{16}\sec^3t$