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Black_prince [1.1K]
3 years ago
11

Help me plzzzz...... .

Mathematics
2 answers:
Vlada [557]3 years ago
7 0

x = 4.5 so it is 3/-8 = 4.5/12

erastovalidia [21]3 years ago
6 0

Answer:

x = \frac{-36}{8} = -4.5

Step-by-step explanation:

WE are given with an equation and we have to solve it for the value of x

As the given equation is

\frac{-3}{8}=\frac{x}{12}

For this we have to use the rule of cross multiplication which states that

if we have two fractions such that

\frac{x}{y}=\frac{a}{b}

then by cross multiplication

b * x = a * y

so similarly for the given equation we have

\frac{-3}{8}=\frac{x}{12}

By cross multiplication

- 3 * 12 = 8 * x

multiplication gives

-36 = 8 x

Dividing both sides by 8

\frac{-36}{8}=\frac{8x}{8}

\frac{-36}{8}=x

So this is the answer in fraction in point form it would be

x = -4.5



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A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

              =1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0
3 years ago
4. What's the least common multiple of each group of numbers?
mina [271]

Answer:

D. 2,5, and 6

Step-by-step explanation:

Because if u mutiply 2*5 = 10 and 2*6 is 12 as 5*6 is 30 and 2*9 is 18 .

8 0
4 years ago
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Anna007 [38]

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4 0
3 years ago
Read 2 more answers
Plss finish fast the question is linked thank you for ur help
kobusy [5.1K]

Answer: B. 2 2/5

Step-by-step explanation: Hope this help :D

3 0
3 years ago
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Ahat [919]
To get the inverse of a function interchange
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y=5x-7


Interchange to get:
x=5y-7
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y=(1/5)x+(7/5)

so I think it might be c


4 0
3 years ago
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