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hammer [34]
3 years ago
5

Janet’s gross pay is $750, from which $31is deducted for OASDI, $10 for Medicare, and $14 for income tax. What is her net pay?

Mathematics
1 answer:
denpristay [2]3 years ago
5 0

Answer:

Net pay = $695

Step-by-step explanation:

To find her net pay, we take the gross pay and minus the deductions

Net pay = 750 - 31 - 10 - 14

Net pay = 695

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A length is measured at 21 cm correct to two significant figures, what is the lower bound of the length and upper bound?
Andreyy89

Answer:

20.5 and 21.5

Step-by-step explanation:

It says 2 significant figures so the least it can possibly be is 0.5 less and the most it can be is 0.5 more as if it was, lets say 20.4 it would round down to 20 not 21.

7 0
2 years ago
HELP PLEASE,<br><br> Part a of the question was posted earlier on.
Elanso [62]
\bf \lim\limits_{x\to 6}~\cfrac{x^2+x+42}{x-6}\implies \lim\limits_{x\to 6}~\cfrac{(x+7)(x-6)}{(x-6)}\implies \lim\limits_{x\to 6}~x+7&#10;\\\\\\&#10;\lim\limits_{x\to 6}~(6)+7=13&#10;\\\\\\&#10;\textit{since the original equation holds for all, }x\ne 6,\textit{ then it approaches}\\&#10;\textit{the same limit as }x+7
3 0
2 years ago
Hello and it would be very helpful if you know these answers!
Wittaler [7]

Answer:

1) 15-4x

2) 3x+2

Step-by-step explanation:

1) product of x and 4 is 4x then subtract that from 15

2) use x as your age in this situation so your age times 3 is 3x and since he's 2 years older than that u add 2 more

5 0
3 years ago
Can someone pls help with this
Anon25 [30]

Answer:

sorry i cant figure this out

7 0
2 years ago
Jerry is mowing his lawn .it takes him 1/6 of an hour to mow 3/20 of his years .what portion of the yard does jerry now per hour
Ber [7]

Given that Jerry mows 3/20 yards of lawn in 1/6 hour.

Now we have to found how much Jerry can mow per hour.

We know that "work" and "time" are in direct proportion so we can setup the ratio of work and time to easily find the required work.

\frac{Portion \; \; of  \; \; lawn  \; \; mowed}{time}=\frac{\frac{3}{20}}{\frac{1}{6}}

\frac{Portion \; \; of  \; \; lawn  \; \; mowed}{1}=\frac{\frac{3}{20}}{\frac{1}{6}}

Portion \; \; of  \; \; lawn  \; \; mowed=\frac{3}{20}*\frac{6}{1}

Portion \; \; of  \; \; lawn  \; \; mowed=\frac{18}{20}

Portion \; \; of  \; \; lawn  \; \; mowed=\frac{9}{10}

Hence final answer is \frac{9}{10} yards.

4 0
3 years ago
Read 2 more answers
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