Question

What are the solutions to the quadratic equation below? 4x^2 + 28x + 49 = 5

Answer 1

Answer:

C.

$x=\frac{-7±\sqrt{5 } }{2}$

Step-by-step explanation:

4x² + 28x + 49 = 5

4x² + 28x + 49 - 5 = 0

4x² + 28x + 44 = 0

4(x² + 7x + 11) = 0

4(x² + 7x + 11) ÷ 4 = 0 ÷ 4

x² + 7x + 11 = 0

$x=\frac{-b±\sqrt{b^{2}-4ac } }{2a}$

Ignore the A before the ±. It wouldn't let me type it correctly.

a = 1

b = 7

c = 11

$x=\frac{-7±\sqrt{7^{2}-4((1)(11)) } }{2(1)}$

$x=\frac{-7±\sqrt{49-4((1)(11)) } }{2(1)}$

$x=\frac{-7±\sqrt{49-44 } }{2(1)}$

$x=\frac{-7±\sqrt{5 } }{2(1)}$

$x=\frac{-7±\sqrt{5 } }{2}$

Answer 2

Answer:

C

Step-by-step explanation: