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sleet_krkn [62]
3 years ago
7

3/4, 1, 5/4 find the 22nd & 43rd terms

Mathematics
1 answer:
natali 33 [55]3 years ago
6 0

Answer:

6 and 45/4

Step-by-step explanation:

If the first three terms of your sequence are 3/4, 1, 5/4, the first term is obviously 3/4 and the common difference is 1/4.  This is an arithmetic sequence.

We can write a general formula for the nth term of this sequence as follows:

a(n) = a(1) + (n-1)(1/4), or, since a(1) = 3/4,

a(n) = 3/4 + (n-1) / 4

Then a(22) = 3/4 + (22-1)/4, or 3/4 + 21/4, or 24/4, or just 6.

a(43) = 3/4 + (43-1)/4, or 3/4 + 42/4, or 45/4.

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The scatter plot shows a scuba diver's depth in the ocean. The equation of the trend link shown is y = -3.29x - 10. Predict what
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<u>It's not given a scatter plot not the characteristics of the variables, but it can be safely assumed as shown below</u>

Answer:

<em>The diver's depth will be -42.9 after 30 minutes</em>

Step-by-step explanation:

The equation of the trend (or best fit line) for the scuba diver's depth in the ocean is:

y = -3.29x - 10

Where y is the diver's depth and x is the time in minutes.

To predict the diver's depth at x=30 minutes, substitute in the equation:

y = -3.29(10) - 10

y = -32.9 - 10

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The diver's depth will be -42.9 after 30 minutes

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3 years ago
Which two tables represent the same function?
topjm [15]

Answer:

The 1st and the 5th tables represent the same function

Step-by-step explanation:

* Lets explain how to solve the problem

- There are five tables of functions, two of them are equal

- To find the two equal function lets find their equations

- The form of the equation of a line whose endpoints are (x1 , y1) and

  (x2 , y2) is \frac{y-y_{1}}{x-x_{1}}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

* Lets make the equation of each table

# (x1 , y1) = (4 , 8) and (x2 , y2) = (6 , 7)

∵ x1 = 4 , x2 = 6 and y1 = 8 , y2 = 7

∴ \frac{y-8}{x-4}=\frac{7-8}{6-4}

∴ \frac{y-8}{x-4}=\frac{-1}{2}

- By using cross multiplication

∴ 2(y - 8) = -1(x - 4) ⇒ simplify

∴ 2y - 16 = -x + 4 ⇒ add x and 16 for two sides

∴ x + 2y = 20 ⇒ (1)

# (x1 , y1) = (4 , 5) and (x2 , y2) = (6 , 4)

∵ x1 = 4 , x2 = 6 and y1 = 5 , y2 = 4

∴ \frac{y-5}{x-4}=\frac{4-5}{6-4}

∴ \frac{y-5}{x-4}=\frac{-1}{2}

- By using cross multiplication

∴ 2(y - 5) = -1(x - 4) ⇒ simplify

∴ 2y - 10 = -x + 4 ⇒ add x and 10 for two sides

∴ x + 2y = 14 ⇒ (2)

# (x1 , y1) = (2 , 8) and (x2 , y2) = (8 , 5)

∵ x1 = 2 , x2 = 8 and y1 = 8 , y2 = 5

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∵ x1 = 2 , x2 = 6 and y1 = 10 , y2 = 14

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∴ y - 10 = x - 2 ⇒ add 2 and subtract y in the two sides

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Step-by-step explanation:

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