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In-s [12.5K]
3 years ago
5

1.3.12

Mathematics
2 answers:
jasenka [17]3 years ago
7 0

Answer:

(0.5,-1.5)

Step-by-step explanation:

this is the numbers i got when I put it in...

m=({-\frac{1+0}{2}  , \frac{-5+2}{2})

(0.5,-1.5)

Elanso [62]3 years ago
7 0

Answer:

S = (2, - 12 )

Step-by-step explanation:

Using the midpoint formula

( \frac{x_{1}+x_{2}  }{2} , \frac{y_{1}+y_{2}  }{2} )

Equate each of the coordinates of the midpoint

let S = (x, y ), then

(x₁, y₁ ) = T(0, 2) and (x₂, y₂ ) = S(x, y ), then

 \frac{0+x}{2} = 1 ( multiply both sides by 2 )

x = 2

\frac{y+2}{2} = - 5 ( multiply both sides by 2 )

y + 2 = - 10 ( subtract 2 from both sides )

y = - 12

S = (2, - 12 )

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3 years ago
Please help me solve my problem!!!
Nookie1986 [14]

Answer:

B. sometimes

Step-by-step explanation:

Consecutive angles of a parallelogram are same side interior angles of two parallel lines cut by a transversal, so they are always supplementary.

Supplementary angles are two angles whose measures add to 180 deg.

If two angles are supplementary and one angle measures 90, then the other angle also measures 90 deg, and the two angles are congruent. If one angle measures less than 90 deg, then the other measure more than 90 deg and are not congruent. Therefore, these angles may or may not be congruent.

Answer: sometimes

7 0
3 years ago
Which is the graph of the function f(x) = x2 + 2x – 6? Mark this and return
valina [46]
Vertex: ( -1, -7 )

Focus: ( -1, -27/4 )

Axis of Symmetry: x = -1

Directrix: y = -29/4


X | Y
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-3| -3
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6 0
3 years ago
Read 2 more answers
The points , (−15,1) and , (−7,r) lie on a line with slope 5/4. Find the missing coordinate r. Click image to enlarge
Nadya [2.5K]

The missing coordinate r is 11.

Solution:

Given points are (–15, 1) and (–7, r).

x_{1}=-15, x_{2}=-7, y_{1}=1 \text { and } y_{2}=7

Slope (m) = \frac{5}{4}

<u>To find the missing coordinate r:</u>

Slope formula:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Substitute the given values in the formula.

$\frac{5}{4}=\frac{r-1}{-7-(-15)}

$\frac{5}{4}=\frac{r-1}{-7+15}

$\frac{5}{4}=\frac{r-1}{8}

Do cross multiplication.

8 \times 5=4(r-1)

40 = 4r – 4

Add 4 on both side of the equation.

44 = 4r

Divide by 4 on both side of the equation.

11 = r

⇒ r = 11

Hence the missing coordinate r is 11.

6 0
3 years ago
Resolve into partial fractions<br><br>​
lisabon 2012 [21]

Answer:

See below

Step-by-step explanation:

1)

\frac{11 + x}{(2 - x)(x - 3)}  =  \frac{A}{2 - x}  +  \frac{B}{x - 3}  \\  \\  \therefore \:  \frac{11 + x}{(2 - x)(x - 3)}  =  \frac{A(x - 3) +B(2 - x) }{(2 - x)(x - 3)}   \\  \\ \therefore \:  11 + x = Ax - 3A + 2B - Bx \\  \\  \therefore \: 11 + x = - 3A  + 2B  + Ax -  Bx\\  \\  \therefore \: 11 + x = - 3A  + 2B  + (A - B)x \\  \\ equating \: the \: like \: terms \: on \: both \: sides \\ A - B = 1 \\  \therefore \: A  =  B  +  1.....(1) \\  \\  -  3A  + 2B = 11....(2) \\  from \: eq \: (1) \: and \: (2) \\  - 3(B  +  1) + + 2B = 11 \\  \\ - 3B   - 3  + 2B = 11 \\  \\  - B = 11 + 3 \\  \\ B =  - 14  \\ A  =   - 14 +  1 =  - 13 \\  \\  \frac{11 + x}{(2 - x)(x - 3)}  =  \frac{ - 13}{2 - x}  +  \frac{ - 14}{x - 3} \\  \\ \frac{11 + x}{(2 - x)(x - 3)}  = -   \frac{ 13}{2 - x}   -  \frac{ 14}{x - 3}

2)

\frac{12x + 11}{x^2 +x - 6}

=\frac{12x + 11}{x^2 +3x-2x - 6}

=\frac{12x + 11}{x(x +3) -2(x +3)}

\therefore \frac{12x + 11}{x^2 +x - 6}=\frac{12x + 11}{(x +3) (x - 2)}

\therefore \frac{12x + 11}{x^2 +x - 6}=\frac{A}{(x +3)}+\frac{B}{(x - 2)}

\therefore \frac{12x + 11}{x^2 +x - 6}=\frac{A(x-2)+B(x+3)}{(x-2)(x+3)}

\therefore 12x + 11 = A(x-2)+B(x+3)

\therefore 12x + 11 = Ax-2A+Bx+3B

\therefore 12x + 11 = Ax+Bx-2A+3B

\therefore 12x + 11 = (A+B) x-2A+3B

Equating like terms on both sides:

A + B = 12\implies A = 12-B... (1)

- 2A + 3B = 11... (2)

Solving equations (1) & (2), we find:

A = 5, B = 7

\therefore \frac{12x + 11}{x^2 +x - 6}=\frac{5}{(x +3)}+\frac{7}{(x - 2)}

3 0
3 years ago
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