Company A pays $5500 more than B in year 10
Answer: 
Step-by-step explanation:
Given : Number of choices for novels = 4
Number of choices for plays = 6
Number of choices for poetry books = 5
Number of choices for nonfiction books = 5
Total books =4+6+5+5=20
If he wants to include all 4 novels, then the number of books left to select = 9-4=5
Remaining choices for books = 20-4=16
Number of combinations of n things taking r at a time : 
Then, the number of different reading schedules are possible :_

Hence, the required answer is
.
The integers are 9 and 10. 9 + 10 = 19. 19^2 = 361
I believe The answer is -92