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I pretty sure the answer is $1086.80
okay so first you have the figure out how many students and teachers they're are gonna be.
so if there's 171 students, and you need 2 adults for every 9 students then you need to divide 171 by 9 because it's 9 to a group so 1721 divided by 9 is 19. now you need to divide that by 2 because theres 19 groups of 9 and you need 2 adults for every 9, so 19 times 2 is 38.
now that you have how many students and teachers are going you need to figure out how much is the total amount of tickets for everyone. if its 4.50 per student and 7.25 per teacher then you need to times $4.50 x 171 students and $7.25 x 38 adults. if you entered it right you should've gotten, $769.50 for the students and $275.50 for adults. add them both up. you should've gotten $1,045.
okay so thats done with now the bus price. so if the bus price is 4% of the total price then you have to times .04 (4% in decimal) times $1045. the answer should be $41.80. so you $41.80 is the bus price now lastly you add that to the mount of the tickets. so last stop. $1045 + $41.80 = 1086.80
So he needs to budget for the amount of $1086.80
I put the work down for you
okay so first you have the figure out how many students and teachers they're are gonna be.
so if there's 171 students, and you need 2 adults for every 9 students then you need to divide 171 by 9 because it's 9 to a group so 1721 divided by 9 is 19. now you need to divide that by 2 because theres 19 groups of 9 and you need 2 adults for every 9, so 19 times 2 is 38.
now that you have how many students and teachers are going you need to figure out how much is the total amount of tickets for everyone. if its 4.50 per student and 7.25 per teacher then you need to times $4.50 x 171 students and $7.25 x 38 adults. if you entered it right you should've gotten, $769.50 for the students and $275.50 for adults. add them both up. you should've gotten $1,045.
okay so thats done with now the bus price. so if the bus price is 4% of the total price then you have to times .04 (4% in decimal) times $1045. the answer should be $41.80. so you $41.80 is the bus price now lastly you add that to the mount of the tickets. so last stop. $1045 + $41.80 = 1086.80
So he needs to budget for the amount of $1086.80
I put the work down for you
Answer:
We conclude that there is an equal or larger proportion of Republicans in favor of lowering the standards.
Step-by-step explanation:
<u>The complete question is</u>: A nationwide sample of influential Republicans and Democrats was asked as a part of a comprehensive survey whether they favored lowering environmental standards so that high-sulfur coal could be burned in coal-fired power plants. The results were:
Number sampled: 1,000 (republican) , 800 (democrats)
Number in favor: 200 (republican) , 168 (democrats)
At the 0.02 level of significance, can we conclude that there is a larger proportion of Democrats in favor of lowering the standards? Determine the p-value.
Let = <u><em>proportion of Republicans in favor of lowering the standards</em></u>.
= <u><em>proportion of Democrats in favor of lowering the standards</em></u>.
SO, Null Hypothesis, :
{means that there is an equal or larger proportion of Republicans in favor of lowering the standards}
Alternate Hypothesis, :
{means that there is a larger proportion of Democrats in favor of lowering the standards}
The test statistics that would be used here <u>Two-sample z-test for</u> <u>proportions</u>;
T.S. = ~ N(0,1)
where, = sample proportion of Republicans in favor of lowering the standards =
= 0.20
= sample proportion of Democrats in favor of lowering the standards =
= 0.21
= sample of Republicans = 1000
= sample of Democrats = 800
So, <u><em>the test statistics</em></u> =
= -0.52
The value of z test statistics is -0.52.
<u>Now, P-value of the test statistics is given by the following formula; </u>
P-value = P(Z < -0.52) = 1 - P(Z 0.52)
= 1 - 0.6985 = 0.3015
Now, at 0.02 significance level, the z table gives a critical value of -2.054 for left-tailed test.
Since our test statistic is more than the critical value of z as -0.52 > -2.054, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <em><u>we fail to reject our null hypothesis</u></em>.
Therefore, we conclude that there is an equal or larger proportion of Republicans in favor of lowering the standards.