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zheka24 [161]
3 years ago
12

ALGEBRA 1, SEM. 2; please show work!

Mathematics
1 answer:
hoa [83]3 years ago
8 0

The enlarged flower bed is a rectangle and its area is x^2+9x+14 m²

So before its enlargement by 14 m², the area of the rectangle = x^2+9x

As you know, the area of rectangle is equal length times width

so area = x^2+9x

factors:

x^2+9x = x (x + 9)

So the dimensions are x and (x + 9)

Hope it helps.


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It’s (-1,0), because
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Is 7- y=5x+11 a standard form
koban [17]

Answer:

No.

Step-by-step explanation:

Because standard form is ax+by=c.

6 0
3 years ago
Given: cos α = 4/5, sin β= 4/5, and α and β are both in quadrant 1. find sin (α+β)
mezya [45]
We have the formula (sin x)^2 + (cos x)^2 = 1;
Then, sin α = \sqrt{1-  ( \frac{4}{5}) ^{2} } =  \frac{3}{5} ;
cos β = \sqrt{1- ( \frac{4}{5}) ^{2} } = \frac{3}{5} ;
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8 0
3 years ago
Can anyone tell me why by direct substitution of x, the equation (circled ones) equals to the indeterminate form, 0/0? When you
Katena32 [7]

Answer:

See explanation and hopefully it answers your question.

Basically because the expression has a hole at x=3.

Step-by-step explanation:

Let h(x)=( x^2-k ) / ( hx-15 )

This function, h, has a hole in the curve at hx-15=0 if it also makes the numerator 0 for the same x value.

Solving for x in that equation:

Adding 15 on both sides:

hx=15

Dividing both sides by h:

x=15/h

For it be a hole, you also must have the numerator is zero at x=15/h.

x^2-k=0 at x=15/h gives:

(15/h)^2-k=0

225/h^2-k=0

k=225/h^2

So if we wanted to evaluate the following limit:

Lim x->15/h ( x^2-k ) / ( hx-15 )

Or

Lim x->15/h ( x^2-(225/h^2) ) / ( hx-15 ) you couldn't use direct substitution because of the hole at x=15/h.

We were ask to evaluate

Lim x->3 ( x^2-k ) / ( hx-15 )

Comparing the two limits h=5 and k=225/h^2=225/25=9.

3 0
2 years ago
Combine like terms to simplify 3x + 3 + 3x + 8=
Over [174]

Answer:

6x + 11

Step-by-step explanation:

3x + 3 + 3x + 8

Combine like terms (terms with the same amount of variables).

3x + 3x + 3 + 8 =

(3x + 3x) + (3 + 8) =

6x + 11

6x + 11 is your answer.

~

3 0
3 years ago
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