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TEA [102]
3 years ago
14

A barbecue restaurant gives 3 napkins for every 5 items ordered. if an order is for 30 items, how many napkins should be given?

Use the double number line diagram to solve.​
Mathematics
2 answers:
Delicious77 [7]3 years ago
8 0

Answer:

18 napkins

Step-by-step explanation:

If the restaurant gives 3 napkins for every 5 items ordered, and there's 30 items... you must divide 30 by 5 which is 6. Then, multiply 6 by 3. Therefore the answer is 18.

30  \div 5 = 6

6 \times 3 = 18

<em>Hope</em><em> </em><em>this</em><em> </em><em>helped</em><em>:</em><em>)</em>

Usimov [2.4K]3 years ago
6 0

Answer:

18 napkins

Step-by-step explanation:

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(a) The median is 1478

(b) Null hypothesis H₀ : μ₁ = μ₂

Alternative hypothesis Hₐ : μ₁ > μ₂

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(d) The p value is  1.2×10⁻¹¹

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Step-by-step explanation:

(a) Here we have the data as follows;

1623 1586 1574 1554 1544 1531 1519 1513 1491 1484 1478 1471 1458 1456 1458 1453 1438 1428 1405 1395 1377

The median is = 1478

Therefore we have above the median  

1623 1586 1574 1554 1544 1531 1519 1513 1491 1484

The mean,  \bar{x}_{1}= 1541.9

Standard deviation, σ₁ = 41.38224257

n₁ = 10

Below the median  

1471 1458 1456 1458 1453 1438 1428 1405 1395 1377

The mean,  \bar{x}_{2}}= 1433.9

Standard deviation, σ₂ = 30.04812806

n₂ = 10

(b) Null hypothesis H₀ : μ₁ = μ₂

Alternative hypothesis Hₐ : μ₁ > μ₂

(c) The formula for t test is given by;

t_{\alpha/2} =\frac{(\bar{x}_{1}-\bar{x}_{2})}{\sqrt{\frac{\sigma_{1}^{2} }{n_{1}}-\frac{\sigma _{2}^{2}}{n_{2}}}}

df = 10 - 1 = 9, α = 0.05

Therefore, the test statistic  t_{\alpha/2} = 6.678155

(d) The p value from statistical relations is Probability p = 1.2×10⁻¹¹

Critical z at 5% confidence level = 1.645

Since P << 0.05, e reject the

(e) Therefore, we reject our null hypothesis H₀. In terms of the test, there is sufficient evidence to suggest that there is a trend in the numbers of daily newspaper because the probability for a decrease in the numbers is very high.

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