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Nutka1998 [239]
3 years ago
11

What is the GREATEST COMMON FACTOR of 20x2 , 10x , and 15?

Mathematics
2 answers:
Umnica [9.8K]3 years ago
7 0

Answer:

5

Step-by-step explanation:

when you divide all the numbers into 5 this is the most greatest common factor

irina [24]3 years ago
6 0

Answer:

5

Step-by-step explanation:

x can only go into 20x2 and 10x and 5 is the Gcf of these three numbers

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Henry and reiko both used 1 yard of ribbon to make bows. write two different fractions to show that Henry and reiko use the same
Natalka [10]
To show that they used the same amount of ribbon you could take the 1 yard and divided into different sized equal groups.

1 yard divided by four equals 1/4 yard for each of four ribbons.

1 yard divided by six equals 1/6 yard for each of six ribbons.

You could have ribbons the size of 1/4 our yard and 1/6 yard, but you would have different amounts of each.
4 0
3 years ago
Four times a first number decreased by a second number is - 14. The first
mel-nik [20]

Answer:

f = -5, s = -6

Step-by-step explanation:

F= first number

S= second number

4f - s = -14

f + 3s = -23

3(4f - s = -14)

12f - 3s = -42

+ f + 3s = -23

13f = -65

————

13

f = -5

4f - s = -14

4(-5) - s = -14

-20 - s = -14

+20 +20

-s = 6

———

-1

s = -6

3 0
3 years ago
A certain pickup truck gets 20mpg in the city and 28 mpg on the highway. If the driver drives 270 mi on 11 gal of gas, determine
Snezhnost [94]

Answer:

95 city and 175 highway miles.

Step-by-step explanation:

The driver gets 20 mpg in city, and 28 mpg on the highway.

An equation that could be written is

20x+28y=270

This equation accounts for the distance traveled.

x+y=11

This equotion accounts for how many gallons were driven.

Multiply the bottom equation by 20, so you can solve the set of equations.

20x+28y=270

20x+20y=220

subtract them

8y=50

y=6.25

now plug this back into x+y=11

x+6.25=11

x=4.75

Now 4.75×20=95 city miles and 6.25×28=175 highway miles.

8 0
3 years ago
Can 40:70 be simplified?
Veseljchak [2.6K]
No they are not equivalent and if you are trying to get a mixed number try dividing
8 0
3 years ago
The numbers on a football field indicate 10 yard increments. You walk around the perimeter of a football field between the pylon
Roman55 [17]

Answer:

5,333 square yards.

Step-by-step explanation:

Football fields have standard 100 yards length, if you walk the perimeter of a football field you will walk the twice the length and twice the width. Therefore, the width of the field can be found as follows:

306.667 = 2L +2W\\W = \frac{306.667 - 2*100}{2} \\W= 53.33

The area of the playing field is the product of the length by the width

A = L*W\\A= 100*53.33\\A=5333

The area of the playing field is 5,333 square yards.

5 0
3 years ago
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