Answer:
The weight of the water in the pool is approximately 60,000 lb·f
Step-by-step explanation:
The details of the swimming pool are;
The dimensions of the rectangular cross-section of the swimming pool = 10 feet × 20 feet
The depth of the pool = 5 feet
The density of the water in the pool = 60 pounds per cubic foot
From the question, we have;
The weight of the water in Pound force = W = The volume of water in the pool given in ft.³ × The density of water in the pool given in lb/ft.³ × Acceleration due to gravity, g
The volume of water in the pool = Cross-sectional area × Depth
∴ The volume of water in the pool = 10 ft. × 20 ft. × 5 ft. = 1,000 ft.³
Acceleration due to gravity, g ≈ 32.09 ft./s²
∴ W = 1,000 ft.³ × 60 lb/ft.³ × 32.09 ft./s² = 266,196.089 N
266,196.089 N ≈ 60,000 lb·f
The weight of the water in the pool ≈ 60,000 lb·f
Answer: Ola
Step-by-step explanation:
Answer:
ratious and axuas
Step-by-step explanation:
A positive number divided by a negative number gives you a negative number for example 12 is positive but the three is negative so our answer has to be negative
3,540 grams of ash
If its density is 2.75 g/cc and
density = mass / volume then its volume is
volume = mass / density
volume = 3,540 g / 2.75 g / cc
volume =
<span>
<span>
<span>
1287.272727 cc
So, rounded it is 1,287.3 cubic centimeters but to keep the same number of significant figures, the volume is
</span></span></span>volume =
<span>
<span>
<span>
1,287 cc</span></span></span>
