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astraxan [27]
3 years ago
10

Mr.Jackson bought 1 3/5 lb.of beef. He cooked 3/4 of it for lunch. How much does he have left

Mathematics
1 answer:
Luda [366]3 years ago
7 0

===> Mr. Jackson bought / . of beef:

===> He cooked / of it for lunch:

Solution ===> Mr Jackson, had 2 / 5 Lbs. left

===> If he cooked / of it for lunch:

===> Mr Jackson, had / of the original amount left.

===> Since ( / )( / )

===> / * /

===> /

Mr Jackson, had / . left.

write the answer as one expression; Then Solve:

( / )( − / )

8 / 5 ( 1 - 3 / 4 )

= 8 / 5 ( 1 / 4 )

= 2 / 5 ( Decimal: 2 / 5 ====> 0.4 )

Answer, 2 / 5 Lbs.; of beef, Mr Jackson, Had left.

Hope that helps!!!!! : )

Hope that Helps!!!! : )

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Slav-nsk [51]
4d = 24 would be the right equation. To double check you would divide both sides by 4 (the number of legs) to find the amount of dogs.
3 0
4 years ago
Please help, super hard question for me!
dem82 [27]

Answer:

Step-by-step explanation:

When using the substitution method we use the fact that if two expressions y and x are of equal value x=y, then x may replace y or vice versa in another expression without changing the value of the expression.

Solve the systems of equations using the substitution method

{y=2x+4

{y=3x+2

We substitute the y in the top equation with the expression for the second equation:

2x+4            =      3x+2

4−2              =        3x−2

2===             =         x

To determine the y-value, we may proceed by inserting our x-value in any of the equations. We select the first equation:

y= 2x + 4

We plug in x=2 and get

y=  2⋅2+4 = 8

The elimination method requires us to add or subtract the equations in order to eliminate either x or y, often one may not proceed with the addition directly without first multiplying either the first or second equation by some value.

Example:

2x−2y = 8

x+y = 1

We now wish to add the two equations but it will not result in either x or y being eliminated. Therefore we must multiply the second equation by 2 on both sides and get:

2x−2y = 8

2x+2y = 2

Now we attempt to add our system of equations. We commence with the x-terms on the left, and the y-terms thereafter and finally with the numbers on the right side:

(2x+2x)  + (−2y+2y) =  8+2

The y-terms have now been eliminated and we now have an equation with only one variable:

4x = 10

x= 10/4 =2.5

Thereafter, in order to determine the y-value we insert x=2.5 in one of the equations. We select the first:

2⋅2.5−2y     =  8

5−8             = 2y

−3               =2y

−3/2            =y

y                 =-1.5

6 0
2 years ago
A study of commuting times reports the travel times to work of a random sample of 20 employed adults in New York State. The mean
Elodia [21]

Answer:

The standard error of the mean = 5.14 mins

Step-by-step explanation:

Number of random sample (n) = 20

Mean(X) = 31.25 mins

Standard deviation (α) = 23.7 mins

Standard error of mean =

standard deviation / √sample size

= 23.7/√20

= 23.7/4.4721

= 5.14 mins

5 0
4 years ago
Angles 4, 5, and 6 are in the ratio 2:5:3. Find the measure of each angle
garri49 [273]

Answer:

The angles 4, 5 and 6 are 36, 90 and 54 respectively.

Step-by-step explanation:

First, let's find the total number of parts:

2 + 5 + 3 = 10

The amount of degrees per part is 180 / 10 = 18.

Now, we multiply that factor to the ratio:

2*18 : 5*18 : 3*18//36:90:54

Thus, the angles 4, 5 and 6 are 36, 90 and 54 respectively.

4 0
4 years ago
Scientists have discovered a vaccine for a debilitating disease. This year there were 570,000 reported new cases of the disease
Ket [755]

Answer: There are approximately 853827 new cases in 6 years.

Step-by-step explanation:

Since we have given that

Initial population = 570000

Rate at which population decreases is given by

\frac{2}{3}

Now,

First year =570000

Second year is given by

570000\times (\frac{1}{3})

Third year is given by

570000(\frac{1}{3})^2

so, there is common ratio ,

it becomes geometric progression, as there is exponential decline.

so,

570000,570000\times \frac{1}{3},570000\times( \frac{1}{3})^2,......,570000\times (\frac{1}{3})^6

a=570000

common ratio is given by

r=\frac{a_2}{a_1}=\frac{1}{3}

number of terms = 6

Sum of terms will be given by

S_n=\frac{a(1-r^n)}{(1-r)}

We'll put this value in this formula,

S_6=\frac{570000(1-(\frac{1}{3})^6}{(1-\frac{1}{3})}\\\\=853827.16

So, there are approximately 853827 new cases in 6 years.

6 0
3 years ago
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