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astraxan [27]
3 years ago
10

Mr.Jackson bought 1 3/5 lb.of beef. He cooked 3/4 of it for lunch. How much does he have left

Mathematics
1 answer:
Luda [366]3 years ago
7 0

===> Mr. Jackson bought / . of beef:

===> He cooked / of it for lunch:

Solution ===> Mr Jackson, had 2 / 5 Lbs. left

===> If he cooked / of it for lunch:

===> Mr Jackson, had / of the original amount left.

===> Since ( / )( / )

===> / * /

===> /

Mr Jackson, had / . left.

write the answer as one expression; Then Solve:

( / )( − / )

8 / 5 ( 1 - 3 / 4 )

= 8 / 5 ( 1 / 4 )

= 2 / 5 ( Decimal: 2 / 5 ====> 0.4 )

Answer, 2 / 5 Lbs.; of beef, Mr Jackson, Had left.

Hope that helps!!!!! : )

Hope that Helps!!!! : )

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<u>Given</u><u> </u><u>:</u>

  • x + y = 4
  • x + y = 1

<u>To</u><u> </u><u>Find</u><u> </u><u>:</u>

  • The value of x and y.

<u>Answer</u><u> </u><u>:</u>

  • x + y = 4 ....[Equation (i)]
  • x + y = 1......[Equation (ii)]

<u>Adding</u><u> </u><u>eqⁿ (ii) </u><u>and</u><u> eqⁿ (i) we get :</u>

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→ x = 5/2

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<u>Now</u><u>,</u><u> </u><u>put</u><u> </u><u>the</u><u> </u><u>value </u><u>of</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>5</u><u>/</u><u>2</u><u> </u><u>in</u><u> </u><u>eqⁿ</u><u> </u><u>(</u><u>i</u><u>)</u><u> </u><u>we</u><u> </u><u>get</u><u> </u><u>:</u>

→ x + y = 4

→ 5/2 + y = 4

→ y = 4 - 5/2

→ y = 1.5

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