3 years ago

How many different orders can be formed for a 9 member baseball team

Mathematics

1 answer:

raketka [301]3 years ago

5 0

Answer:

362,880

Step-by-step explanation:

If there are 9 players for the 1st position, 8 for the 2nd and so on so on, you can multiply all the numbers 1-9 together (i.e 9×8×7×6×5×4×3×2×1= 362,880)

**This is if it's asking for how many different batting orders are possible**

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Hey there :)

- tan²x + sec²x = 1 or 1 + tan²x = sec²x

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mario62 [17]

Answer:

Step-by-step explanation:

from the graph of f(x)

when x=1,f(x)=0

or f(1)=0

when f(x)=2,x=2

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when x=6,g(x)=16

or g(6)=16

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3 years ago