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2 years ago

@spongebobdid91 I seriously don't know how I should start with this....

Mathematics

1 answer:

Serjik [45]2 years ago

7 0

You have a straight line, cut by another creating angles...u do 180 - 130 which is 50, that's the inside angle, and 180 - 134 which is 46, another inside angle so u add the inside angle, 50 + 46 =96 we have the sum of 2 angles out of 3 in the triangle so we move on to get the final angle of the triangle. 180 - 96 = 84. X is the outside of that last angle we found so 180 - 84 = x = 96

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An arithmetic sequence is given below.

Mashcka [7]

Given that $a_1=24$ and $a_2=17$ , if $a_n$ is an arithmetic sequence, then the common difference between successive terms is $d=a_2-a_1=17-24=-7$ .

You then have

$a_2=a_1+d$
$\implies a_3=a_2+d=a_1+2d$
$\implies a_4=a_3+d=a_1+3d$
$\implies \cdots\implies a_n=a_{n-1}+d=\cdots=a_1+(n-1)d$

So the explicit formula for the $n$ th term is

$a_n=24-7(n-1)$

3 0

3 years ago

What is the distance between -60 and -10 0n a number line?

JulsSmile [24]

Answer: 70

Step-by-step explanation: The absolute value of a number is its distance from zero on the number line. Since absolute value is a distance, it is always greater than or equal to zero.

5 0

2 years ago

URGENT!! NEED THIS IN TWO HOURS. DUMB ANSWERS WILL BE REPORTED ALTHOUGH I UNDERSTAND IF YOU MAKE A SIMPLE MISTAKE IN YOUR CALCUL

Andre45 [30]

Yo sup??

The given points are (1,1),(1,3) and (9,2)

equation of circle is

8x²+8y²+ax+by=0

let us plug in (1,1) in the equation we get

8+8+a+b=0

a+b=-16

let us now plug in (1,3) in the equation

8+8*3²+a+3b=0

a+3b=-80

let us. now solve the two equation in terms of a and b

we get

2b=--64

b=-32

and

a=-16+32

=16

therefore the equation is

8x²+8y²+16x-32y=0

Hope this helps

6 0

2 years ago

I need help. this is the problem x^2/3+10=7x^1/3

Arlecino [84]

$\it x^{\frac{2}{3}}+10=7x^{\frac{1}{3}} \Leftrightarrow (x^{\frac{1}{3}})^2-7x^{\frac{1}
 {3}} +10=0 
\\\;\\
We\ note\ x^{\frac{1}{3}} =t \ \ and \ the \ equation \ will \ be:
\\\;\\
t^2-7t+10 = 0 \Leftrightarrow t^2 -2t-5t+10=0 \Leftrightarrow t(t-2) -5(t-2)=0$

$\it \Leftrightarrow (t-2)(t-5)=0 
\\\;\\
t-2=0 \Rightarrow t=2 \Rightarrow x^{\frac{1}{3}}=2 \Rightarrow (x^{\frac{1}{3}})^3 =2^3 \Rightarrow x = 8
\\\;\\
t-5=0 \Rightarrow t=5 \Rightarrow x^{\frac{1}{3}}= 5 \Rightarrow (x^{\frac{1}{3}})^3 = 5^3 \Rightarrow x = 125$

S = {8; 125}

7 0

3 years ago

How do you find the f(x) inverse using fractions?

fenix001 [56]

For example.. 1) switch places of x and y. x=3y+1 x=3 y +1
2) try to solve for y. so multiply the denominator by x to get rid of it
3) after multiplying, ur left with xy+x=3 x y + x=3
4) that converts to 2xy= x y =3
5) get rid of 2x on left by placing it on the right
6) convert y to inverse function

4 0

2 years ago