Answer:
Let O be the center of a circle whose radius is r cm , in which AB= 14 cm long
cord is at a distanceof 24 cm from O. Draw a perpendicular OD on AB , thus ,
OD= 24 cm.
In right angled triangle. ODB
OB^2 = OD^2+ DB^2
r^2 =(24)^2+(AB/2)^2 = 576+(14/2)^2
r^2 = 576+ 49=625
r = √625. =25 cm. Answer.
Answer:
60ft
Step-by-step explanation:
Let's x, y be the width and length of the surrounding rectangle. Since the area is 450 sq feet, this means xy = 450 or y = 450/x
The perimeter of this rectangle is (since there are 3 sides only)
f(x,y) = 2x + y
This is something we need to minimize. We can start by substituting y = 450/x
f(x) = 2x + 450/x
Let's take the first derivative of this function and set it to 0




y = 450 / 15 = 30ft
so the minimum perimeter that needs taping over is
f(x,y) = 2x + y = 2*15 + 30 = 60ft
A) 1.15
B) 2.87
C) 3.59
D) 4.22
E) 5.74
F) 6.95
G) 7.25
H) 8.64
I) 9.68
J) 28.33
Area= l*b
0.8=3.2*x
0.8/3.2=x
x=0.25 units
First one simplifies to 2x + 6 = 2x + 7 which can't be true so this one has No Solution.
Same applies to the second equation ( 5x + 15 = 5x - 15) No solution
also the last one has no solution because it simplifies to 4x + 20 = 4x + 19