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3 years ago

What is the kinetic energy, in joules, of an object that has a mass of 100 kilograms and moves with a velocity of 10 m/s?

Mathematics

1 answer:

Over [174]3 years ago

6 0

Given, an object with a mass of 100kg.

The velocity given 10m/s.

Kinetic energy is directly proportional to the mass of the object and to the square of its velocity.

The formula to find Kinetic energy is

K.E = 1/2 × m × v² ( where m = mass and v = velocity)

= 1/2 × (100) × (10)²

= 1/2 × (100) × (100)

= 1/2 × (10000)

= 5000

We have got the required answer.

The required kinetic energy is 5000 joules.

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What is the best estimate for the volume of the pyramid?

laila [671]

Volume of the pyramid = (1/3) * base area * height
Base area = 230² = 52,900 m²
Volume of the pyramid = (1/3) * 52,900 * 138 = 2,433,400 m³

6 0

3 years ago

56 = −8d + 8 there's not multiple answers

ollegr [7]

Answer:

d= -6

Step-by-step explanation:

56 = -8d + 8

1) You want to get d by itself. Subtract 8 from both sides.

56 = -8d + 8

- 8 - 8

(8 - 8 = 0, and 56 - 8 is 48.)

48 = -8d

2) Then, you divide my -8 on both sides.

(48 / -8 is -6, and -8d / -8 is just d.)

-6 = d

So, d = -6

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4 years ago

A hairdresser combined three bottles of shampoo into one bottle. The first bottle had 4.8 ounces of shampoo, the second bottle h

Korvikt [17]

Answer:

about 20

Step-by-step explanation:

its kindergarden math

6 0

3 years ago

Tiana has already taken 1 page of notes on her own, and she will take 1 page during each hour of class. In all, how many hours w

Novosadov [1.4K]

Answer:

42 Hours.

Step-by-step explanation:

As an equation where y is the total pages and x is hours of class:

y=1+1x since she started with 1 page and does 1 page per hour.

Setting the total pages she needs as 43 (y=43) we get:

43=1+1x

Subtract one on both sides

42=1x

The 1 doesn't need to be written so

x=42

Therefore, it'll take her 42 hours to write all those notes.

4 0

3 years ago

Slices of pizza for a certain brand of pizza have a mass that is approximately normally distributed with a mean of 67.7 grams an

Alexxx [7]

Answer:

a. s.e. = 0.338

b. The probability of finding a random slice of pizza with a mass of less than 67.2 grams is 0.5871 or 58.71%

c. The probability of finding a 20 random slices of pizza with a mean mass of less than 67.2 grams is 0.0694 or 6.94%

d. The sample mean of 62.75 would represent the 15th percentile

Step-by-step explanation:

1. Let's review the information provided to us to answer the question properly:

μ of the mass of slices of pizza for a certain brand = 67.7 grams

σ of the mass of slices of pizza for a certain brand = 2.28 grams

2. For samples of size 20 pizza slices, what is the standard deviation for the sampling distribution of the sample mean?

Let's recall that the standard deviation of the sampling distribution of the mean is called the standard error of the mean and its formula is:

μσs.e.= √σ/n, where n is the sample size.

s.e. = √2.28/20

s.e. = 0.338

3. What is the probability of finding a random slice of pizza with a mass of less than 67.2 grams?

Let's find the z-score for X = 67.2, this way:

z-score = (X - μ)/σ

z-score = (67.2 - 67.7)/2.28

z-score = 0.5/2.28

z-score = 0.22 (rounding to the next hundredth)

Now, using the z-table, let's find p, the probability:

p (z = 0.22) = 0.5871

The probability of finding a random slice of pizza with a mass of less than 67.2 grams is 58.71%

4. What is the probability of finding a 20 random slices of pizza with a mean mass of less than 67.2 grams?

Let's use the central limit theorem to find the z-score, this way:

z-score = X - μ/s.e

z-score = 67.2 - 67.7/0.338

z-score = -0.5/0.338

z-score = - 1.48

Now, using the z-table, let's find p, the probability:

p (z = -1.48) = 0.0694

5. What sample mean (for a sample of size 20) would represent the bottom 15% (the 15th percentile)?

For p = 0.150, let's find the z-score:

z-score = - 2.17

z-score = X - μ/s.e

- 2.17 = (X - 67.7)/2.28

- 4.95 = X - 67.7

X = 67.7 - 4.95

X = 62.75 (rounding to the next hundredth)

The sample mean of 62.75 would represent the 15th percentile

7 0

3 years ago