Answer:
£73.71
Step-by-step explanation:
Let's compute first for the cost of the ticket in <em>2014</em>. Let x be the<em> increase in the cost of the ticket.</em> If the cost of the ticket is 8% of £65, then the expression should be like this:
- x = 65 x 8%
- x = 65 x 0.08
- x = £5.2
Let's add £5.2 to £65 ⇒ £5.2 + £65 = £70.2
The cost of the season ticket in 2014 is £70.2.
Next, we'll have to compute the cost of the ticket in<em> 2015</em>. Let y be the <em>increase in cost of the ticket</em>. If the cost of the ticket is 5% of £70.2, then the expression should be like this:
- y = 70.2 x 5%
- y = 70.2 x 0.05
- y = £3.51
Let's add £3.51 to £70.2 ⇒ £3.51 + £70.2 = £73.71
The cost of the season ticket in 2015 is £73.71. <em>This is also the cost of the season ticket after two price increases.</em>
Answer:
11 c; 12 c; 13 b
Step-by-step explanation:
Question 11
![\text{Volume} = \text{4 doses} \times \dfrac{\text{2 T}}{\text{1 dose}}\times \dfrac{\text{15 mL}}{\text{1 T}} = \textbf{120 mL}](https://tex.z-dn.net/?f=%5Ctext%7BVolume%7D%20%3D%20%5Ctext%7B4%20doses%7D%20%5Ctimes%20%5Cdfrac%7B%5Ctext%7B2%20T%7D%7D%7B%5Ctext%7B1%20dose%7D%7D%5Ctimes%20%5Cdfrac%7B%5Ctext%7B15%20mL%7D%7D%7B%5Ctext%7B1%20T%7D%7D%20%3D%20%5Ctextbf%7B120%20mL%7D)
Question 12
(a) Add up the total fluid ounces
![\begin{array}{rr}\textbf{Liquid} & \textbf{V/oz} \\\text{Juice} & 6 \\\text{Water} & 4 \\\text{Soda} & 8 \\\text{Coffee} & 10 \\\text{Milk} & 6 \\\text{Total fluids} & 34 \\\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Brr%7D%5Ctextbf%7BLiquid%7D%20%26%20%5Ctextbf%7BV%2Foz%7D%20%5C%5C%5Ctext%7BJuice%7D%20%26%206%20%5C%5C%5Ctext%7BWater%7D%20%26%204%20%5C%5C%5Ctext%7BSoda%7D%20%26%208%20%5C%5C%5Ctext%7BCoffee%7D%20%26%2010%20%5C%5C%5Ctext%7BMilk%7D%20%26%206%20%5C%5C%5Ctext%7BTotal%20fluids%7D%20%26%2034%20%5C%5C%5Cend%7Barray%7D)
(b) Convert fluid ounces to millilitres
![\text{Volume} = \text{34 oz} \times \dfrac{\text{15 mL}}{\text{1 oz }} = \textbf{510 mL}](https://tex.z-dn.net/?f=%5Ctext%7BVolume%7D%20%3D%20%5Ctext%7B34%20oz%7D%20%5Ctimes%20%5Cdfrac%7B%5Ctext%7B15%20mL%7D%7D%7B%5Ctext%7B1%20oz%20%7D%7D%20%3D%20%5Ctextbf%7B510%20mL%7D)
Question 13
1 L =10 dL
![\text{Volume} = \text{80 dL} \times \dfrac{\text{1 L}}{\text{10 dL}} = \textbf{8.0 L}](https://tex.z-dn.net/?f=%5Ctext%7BVolume%7D%20%3D%20%5Ctext%7B80%20dL%7D%20%5Ctimes%20%5Cdfrac%7B%5Ctext%7B1%20L%7D%7D%7B%5Ctext%7B10%20dL%7D%7D%20%3D%20%5Ctextbf%7B8.0%20L%7D)
Answer:
jus draw a m-f trapizod from googl-e
Step-by-step explanation:
The 0 in the hundred thousands place would not be represented because it is nil.