Question

roger can run one mile in 21 minutes. jeff can run one mile in 18 minutes. if jeff gives roger a 1 minute head start, how long will it take before jeff catches up to roger? how far will each have to run?

Answer 1

x/16 = (x-1)/14

14x = 16x-16

2x = 16

x = 8 minutes (Roger time)

Roger will run rt = (1/16)8 = 1/2 mile

x-1 = 7 minutes (Jeff time)

Jeff will run rt = (1/14)7 = 1/2 mile