First let's make the denominators of the fractions equal.
To do this, we have to find a number which both 5 and 7 divide into.
The smallest number that does this is 35.
2 --> Multiply the numerator by 7
--
5 --> Multiply the denominator by 7 to get 35
= 14/35
1 --> Multiply the numerator by 5
--
7 --> Multiply the denominator by 5 to get 35
= 5/35
Joe has eaten 14/35 and James has eaten 5/35.
14 / 5 = 2.8
<u>Joe has eaten 2.8 (or 2 4/5) times more pizza than James.</u>
Answer:
![\left[\begin{array}{ccc}32&-55\\3&39\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D32%26-55%5C%5C3%2639%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
![\left[\begin{array}{ccc}0&-15\\3&15\end{array}\right] +\left[\begin{array}{ccc}32&-40\\0&24\end{array}\right] =\left[\begin{array}{ccc}0+32&-15+(-40)\\3+0&15+24\end{array}\right] = \left[\begin{array}{ccc}32&-55\\3&39\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%26-15%5C%5C3%2615%5Cend%7Barray%7D%5Cright%5D%20%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D32%26-40%5C%5C0%2624%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%2B32%26-15%2B%28-40%29%5C%5C3%2B0%2615%2B24%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D32%26-55%5C%5C3%2639%5Cend%7Barray%7D%5Cright%5D)
B, because people do selective breeding to get something they want out of it. Which decreases genetic diversity, genetic diversity meaning there being less and less traits and characteristics and we wont something perfect not exactly something with traits that we dont like. However dont get me wrong, nothings perfect. But yeah.
12/10, 1.2, and any of the infinite multiples of the fraction such as 24/20, 120/100 etc...
Answer:
70 is answer
Step-by-step explanation:
Given that a function in x is
![f(x) = 5x^2](https://tex.z-dn.net/?f=f%28x%29%20%3D%205x%5E2)
we have to find f'(7)
we know by derivative rule derivative of a function is
![f'(x) = lim_({h-->0}) \frac{f(x+h)-f(x)}{h}](https://tex.z-dn.net/?f=f%27%28x%29%20%3D%20lim_%28%7Bh--%3E0%7D%29%20%5Cfrac%7Bf%28x%2Bh%29-f%28x%29%7D%7Bh%7D)
For finding out at 7 we replace x by 7
![f'(7) = lim_({h-->0}) \frac{f(7+h)-f(7)}{h}](https://tex.z-dn.net/?f=f%27%287%29%20%3D%20lim_%28%7Bh--%3E0%7D%29%20%5Cfrac%7Bf%287%2Bh%29-f%287%29%7D%7Bh%7D)
=![lim\frac{5(7+h)^2-5*7^2}{h} \\= lim \frac{10h*7+h^2}{h} \\= 70+h = 70](https://tex.z-dn.net/?f=lim%5Cfrac%7B5%287%2Bh%29%5E2-5%2A7%5E2%7D%7Bh%7D%20%5C%5C%3D%20lim%20%5Cfrac%7B10h%2A7%2Bh%5E2%7D%7Bh%7D%20%5C%5C%3D%2070%2Bh%20%3D%2070)
So f'(7) = 70
answer is 70