Answer:
The answer is "Options A, B, and E represent mutually exclusive events".
Step-by-step explanation:
Two occurrences that can happen immediately called mutually incompatible. Let's now glance at our options and figure out where the statements are mutually incompatible events.
In Option A: You could see that landing on an unwanted portion and arriving on 2 are events that are locally incompatible, even as undesirable portion contains 3 and 4, and 2 were shaded.
In Option B: Arriving on a shaded part and falling on 3 are also mutually incompatible because there are 3 on a windows azure.
In Option C: A darkened portion and an increasing amount can land while 2 would be an even number as well as on the shaded portion. That number is very much the same.
In Option D: At the same time as 4 is greater than 3 and it is situated upon an undistressed section, landing and attracting a number larger than 3 can happen.
In Option E: Landing on a shaded part and landing on even a shaded part is an excluding event, since shaders may either be shaded or unlit.
Answer:
167 adult tickets were sold
35 children tickets were sold
Step-by-step explanation:
Let the number of adult tickets be x
Let the number of children tickets be y
Total number of each ticket sold;
x + y = 202 equation 1
Total cost of the tickets
10x + 6y = 1708 equation 2
Let
x= 202 - y equation 3
Substitute 3 into 2
10(202 - y) + y = 1708
2020 - 10y + y = 1708
-9y = 1708 - 2020
-9y = -312
y= 35
Substitute y =35 into 1
x + 35 =202
x= 202 - 35
x= 167
Therefore;
167 adult tickets were sold
35 children tickets were sold
Answer:
x = 12
Step-by-step explanation:
4x+40 = 100-x
so when solved the answer is 12.
I hope this helps you.
Answer:
on flipping a coin, we either get a heads or a tails and both the events are equally likely. So the probablity of getting a tails is 1/2.
Now
On rolling a die, we can get 6 possible outcomes(1,2,3,4,5,6)
But the favourable outcomes (an even number) are only 3. So the probablity of getting an even number is 3/6=1/2
In case. we have 2 events that need to occur together, we simply need to multiply their individual probablities to get the probablity of getting both the events together
So our required answer is
p(even number)× p(tails)= 1/2 × 1/2 = 1/4
Step-by-step explanation: