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Alona [7]
3 years ago
7

I need help once again.

Mathematics
1 answer:
muminat3 years ago
8 0
The dimensions of the prism can be 2x, 2x+3 and x+6.

We first factor out the GCF of the trinomial.  The GCF of the coefficients is 2.  Each term has an x in common as well, so the GCF is 2x.

Factoring out the 2x, we have
2x(2x²+15x+18).

To factor the remaining trinomial, we find factors of 2*18=36 that sum to 15.  12*3 = 36 and 12+3 = 15.  We split up 15x into 12x and 3x:

2x(2x²+12x+3x+18)

Now we group together the first two terms in parentheses and the last two:
2x((2x²+12x)+(3x+18))

Factor out the GCF of the first group:
2x(2x(x+6)+(3x+18))

Factor out the GCF of the second group:
2x(2x(x+6)+3(x+6))

Factoring out what these have in common,
2x(x+6)(2x+3)
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One hundred items are simultaneously put on a life test. Suppose the lifetimes
romanna [79]

Answer:

a) \mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}

b) \mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}

Step-by-step explanation:

Given:

The lifetimes of the individual items are independent exponential random variables.

Mean = 200 hours.

Assume, Ti be the time between ( i-1 )st and the ith failures. Then, the T_{i} are independent with \mathrm{T}_{\mathrm{i}} being exponential with rate \frac{(101-i)}{200} .

Therefore,

a) E[T]=\sum_{i=1}^{5} E\left[\tau_{i}\right]

=\sum_{i=1}^{5} \frac{200}{101-i}

\therefore \mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}

b)

The variance is given by, \mathrm{Var}[\mathrm{T}]=\sum_{i=1}^{5} \mathrm{Var}[T]

\therefore \mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}

7 0
3 years ago
Quizizz 10 pts each help please WITH PIC brainiest guaranteed
lawyer [7]

Answer:

2.-2m^4-6m^2+4m+9

3.-2m^4-6m^2-4m+9

Step-by-step explanation:

<em>In general we can write a polynomial in standard form as </em>

ax^n+bx^n^-^1+cx^n^-^2+...+px+q

<em>Given</em> 4m-2m^4-6m^2-4m+9

<em>Combine the like terms: 4m and -4m</em>

<em>4m-4m=0</em>

<em>We have 4m-4m=0</em>

<em>So, write the remaining terms</em>

-2m^4-6m^2+9+0

= -2m^4-6m^2+9

<em>This is in decreasing order of powers.</em>

<em>Hence the answer is the standard form is</em>

-2m^3-6m^2+9

<em>But in the given options, you can choose option 2 and option 3 are in standard form.</em>

<em>Because they are in decreasing order of powers.</em>

<em>In other two options, the constants term is first and the highest power term is at the last. So, they are not in standard form.</em>

<em>-2m^4-6m^2+4m+9</em>

<em>-2m^4-6m^2-4m+9</em>

<em>I hope this helps you.</em>

<em>And please comment if I need to do corrections.</em>

<em>Please let me know if you have any questions.</em>

8 0
3 years ago
Please help me quickly, timed test:(​
Dennis_Churaev [7]

Answer:

1 & 7

Step-by-step explanation:

I guessed. Good Luck!

7 0
2 years ago
Read 2 more answers
Point B is the center of a circle, and AC is a diameter of the circle. Point D is a point on the circle different from A and C.
seropon [69]

BA and BD are radii of the circle, so triangle ABD is isosceles. Then angles BDA and BAD are congruent, and the remaining (central) angle ABD has measure

m\angle ABD=(180-2\cdot20)^\circ=140^\circ

Angles ABD and CBD are supplementary, so

m\angle CBD=(180-140)^\circ=40^\circ

and the answer is E.

8 0
3 years ago
Which equation are equivalent to 1/5+2/3|2-x|=4/15?
disa [49]

Answer:

• 2/3|2 -x| = 1/15

• |2 -x| = 1/10

• 1/5 +|4/3 -2/3x| = 4/15

Step-by-step explanation:

Starting with the given equation, subtract 1/5 = 3/15.

(2/3)|2 -x| = 4/15 - 3/15

(2/3)|2 -x| = 1/15 . . . . . . . . matches the first choice

Now, multiply by 3/2.

|2 -x| = 3/30

|2 -x| = 1/10 . . . . . . . . . . . . matches the third choice

___

If you decide to distribute the coefficient 2/3 instead, you have

1/5 + |2·2/3 -x·2/3| = 4/15

1/5 + |4/3 -2/3x| = 4/15 . . . . matches the selected choice

5 0
3 years ago
Read 2 more answers
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