Answer:
a) ![\mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}](https://tex.z-dn.net/?f=%5Cmathrm%7BE%7D%5B%5Cmathrm%7BT%7D%5D%3D%5Csum_%7B%5Cmathrm%7BH%7D%7D%5E%7B5%7D%20%5Cfrac%7B200%7D%7B101-i%7D)
b) ![\mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}](https://tex.z-dn.net/?f=%5Cmathrm%7BVar%7D%5B%5Cmathrm%7BT%7D%5D%3D%5Csum_%7Bk%3D1%7D%5E%7B5%7D%20%5Cfrac%7B%28200%29%5E%7B2%7D%7D%7B%28101-i%29%5E%7B2%7D%7D)
Step-by-step explanation:
Given:
The lifetimes of the individual items are independent exponential random variables.
Mean = 200 hours.
Assume, Ti be the time between (
)st and the
failures. Then, the
are independent with
being exponential with rate
Therefore,
a) ![E[T]=\sum_{i=1}^{5} E\left[\tau_{i}\right]](https://tex.z-dn.net/?f=E%5BT%5D%3D%5Csum_%7Bi%3D1%7D%5E%7B5%7D%20E%5Cleft%5B%5Ctau_%7Bi%7D%5Cright%5D)

![\therefore \mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}](https://tex.z-dn.net/?f=%5Ctherefore%20%5Cmathrm%7BE%7D%5B%5Cmathrm%7BT%7D%5D%3D%5Csum_%7B%5Cmathrm%7BH%7D%7D%5E%7B5%7D%20%5Cfrac%7B200%7D%7B101-i%7D)

The variance is given by, ![\mathrm{Var}[\mathrm{T}]=\sum_{i=1}^{5} \mathrm{Var}[T]](https://tex.z-dn.net/?f=%5Cmathrm%7BVar%7D%5B%5Cmathrm%7BT%7D%5D%3D%5Csum_%7Bi%3D1%7D%5E%7B5%7D%20%5Cmathrm%7BVar%7D%5BT%5D)
![\therefore \mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}](https://tex.z-dn.net/?f=%5Ctherefore%20%5Cmathrm%7BVar%7D%5B%5Cmathrm%7BT%7D%5D%3D%5Csum_%7Bk%3D1%7D%5E%7B5%7D%20%5Cfrac%7B%28200%29%5E%7B2%7D%7D%7B%28101-i%29%5E%7B2%7D%7D)
Answer:
2.
3.
Step-by-step explanation:
<em>In general we can write a polynomial in standard form as </em>

<em>Given</em> 
<em>Combine the like terms: 4m and -4m</em>
<em>4m-4m=0</em>
<em>We have 4m-4m=0</em>
<em>So, write the remaining terms</em>

= 
<em>This is in decreasing order of powers.</em>
<em>Hence the answer is the standard form is</em>

<em>But in the given options, you can choose option 2 and option 3 are in standard form.</em>
<em>Because they are in decreasing order of powers.</em>
<em>In other two options, the constants term is first and the highest power term is at the last. So, they are not in standard form.</em>
<em>-2m^4-6m^2+4m+9</em>
<em>-2m^4-6m^2-4m+9</em>
<em>I hope this helps you.</em>
<em>And please comment if I need to do corrections.</em>
<em>Please let me know if you have any questions.</em>
Answer:
1 & 7
Step-by-step explanation:
I guessed. Good Luck!
BA and BD are radii of the circle, so triangle ABD is isosceles. Then angles BDA and BAD are congruent, and the remaining (central) angle ABD has measure

Angles ABD and CBD are supplementary, so

and the answer is E.
Answer:
• 2/3|2 -x| = 1/15
• |2 -x| = 1/10
• 1/5 +|4/3 -2/3x| = 4/15
Step-by-step explanation:
Starting with the given equation, subtract 1/5 = 3/15.
(2/3)|2 -x| = 4/15 - 3/15
(2/3)|2 -x| = 1/15 . . . . . . . . matches the first choice
Now, multiply by 3/2.
|2 -x| = 3/30
|2 -x| = 1/10 . . . . . . . . . . . . matches the third choice
___
If you decide to distribute the coefficient 2/3 instead, you have
1/5 + |2·2/3 -x·2/3| = 4/15
1/5 + |4/3 -2/3x| = 4/15 . . . . matches the selected choice