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babunello [35]
4 years ago
6

Since the ratios for sides of triangles are the same, when the angles are the same, ? have been developed which show these ratio

s for every angle encountered in a triangle. select one:
a. cos tables
b. sin tables
c. tan tables
d. trigonometric tables
Mathematics
2 answers:
statuscvo [17]4 years ago
7 0

Answer: d. trigonometric tables


Step-by-step explanation:

A trigonometric table would provide all of the ratios of the sides in respect to the angles. Sin, cos, and tan are parts of trigonometric table.

Trigonometry table, tabulated values for some or all of the six trigonometric functions for various angular values.

Since the ratios for sides of triangles are the same, when the angles are the same, trigonometric tables have been developed which show these ratios for every angle encountered in a triangle.

Scilla [17]4 years ago
4 0
Presuming that I am reading the question correctly, the answer is D. A trigonometric table would provide all of the ratios of the sides in relationship to the angles. Sin, cos, and tan are just one example of the ratio.
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creativ13 [48]

Answer:

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1.) Write in standard form: one hundred fifty-three and fifty-one<br> hundredths.
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153.51

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3 years ago
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You must design a closed rectangular box of width w, length l and height h, whose volume is 504 cm3. The sides of the box cost 3
Charra [1.4K]

Answer:

Dimensions will be

Length = 7.23 cm

Width = 7.23 cm

Height = 9.64 cm

Step-by-step explanation:

A closed box has length = l cm

width of the box = w cm

height of the box = h cm

Volume of the rectangular box = lwh

504 = lwh

h=\frac{504}{lw}

Sides which involve length and width and height, cost = 3 cents per cm²

Top and bottom of the box costs = 4 cents per cm²

Cost of the sides C_{s}= 3[2(l + w)h] = 6(l + w)h

C_{s}= 3[2(l + w)h]

C_{s}=6(l+w)(\frac{504}{lw} )

Cost of the top and the bottom C_{(t,p)}= 4(2lw) = 8lw

Total cost of the box C = 3024\frac{(l+w)}{lw} + 8lw

                                      = 3024[\frac{1}{l}+\frac{1}{w}] + 8lw

To minimize the cost of the sides

\frac{dC}{dl}=3024(-l^{-2}+0)+8w=0

\frac{3024}{l^{2}}=8w

\frac{378}{l^{2}}=w ---------(1)

\frac{dC}{dw}=3024(-w^{-2})+8l=0

\frac{3024}{w^{2}}=8l

\frac{378}{w^{2}}=l

w^{2}=\frac{378}{l}-------(2)

Now place the value of w from equation (1) to equation (2)

(\frac{378}{l^{2}})^{2}=\frac{378}{l}

\frac{(378)^{2} }{l^{4}}=\frac{378}{l}

l³ = 378

l = ∛378 = 7.23 cm

From equation (2)

w^{2}=\frac{378}{7.23}

w^{2}=52.28

w = 7.23 cm

As lwh = 504 cm³

(7.23)²h = 504

h=\frac{504}{(7.23)^{2}}

h = 9.64 cm                        

6 0
4 years ago
5 / 3 x + 1 / 3x equals 13 + 1 / 3 x + 8 / 3 x
NNADVOKAT [17]

Answer: x = - 12/9 ( the equation is negative)

Step-by-step explanation:

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\frac{5}{3}x-3x=3x+\frac{38}{3}-3x

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3 years ago
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Misha Larkins [42]

Answer:

a. P (R3 | G1)=\frac{1}{5}

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Step-by-step explanation:

The sample space associated with the random experiment of throwing a dice is is the equiprobable space {R1, R2, R3, R4, R5, R6}. Then,

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b. What is the conditional probability that 6 is rolled given that the roll is greater than 3? P (R6| G3) = \frac{P (R6\bigcap G3)}{P(G3)} = \frac{1/6}{3/6} = \frac{1}{3}

c. What is P [GIE], the conditional probability that the roll is greater than 3 given that the roll is even? P(G3|E) = \frac{P (G3\bigcap E)}{P(E)} = \frac{2/6}{3/6} = \frac{2}{3}

d. Given that the roll is greater than 3, what is the conditional probability that the roll is even? P (E|G3) = \frac{P (E\bigcap G3)}{P(G3)} = \frac{2/6}{3/6} = \frac{2}{3}

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3 years ago
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