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3 years ago

1.) Write in standard form: one hundred fifty-three and fifty-one hundredths.

Mathematics

2 answers:

Jobisdone [24]3 years ago

7 0

Answer:

153.51

Look at a number place value chart which can help you

ASHA 777 [7]3 years ago

5 0

Answer:

153.51

Step-by-step explanation:

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What is the value of 4/15, divided by, 2/ 3?<br> help plzzz

fgiga [73]

Answer: 2/5

Step-by-step explanation: Dividing two fractions is the same as multiplying the first fraction by the reciprocal (inverse) of the second fraction

Take the reciprocal of the second fraction by flipping the numerator and denominator and changing the operation to multiplication. Then the equation becomes

The, multiply the numerators and denominators and get 12/30, then simply by 6 and get 2/5

5 0

3 years ago

A random variable x follows a normal distribution with mean d and standard deviation o=2. It is known that x is less than 5 abou

Vaselesa [24]

Answer:

The mean of this distribution is approximately 3.96.

Step-by-step explanation:

Here's how to solve this problem using a normal distribution table.

Let $z$ be the

$\displaystyle z = \frac{x - \mu}{\sigma}$ .

In this question, $x = 5$ and $\sigma = 2$ . The equation becomes

$\displaystyle z = \frac{5 - \mu}{2}$ .

To solve for $\mu$ , the mean of this distribution, the only thing that needs to be found is the value of $z$ . Since

The problem stated that $P(X \le 5) = 69.85\% = 0.6985$ . Hence, $P(Z \le z) = 0.6985$ .

The problem is that the normal distribution tables list only the value of $P(0 \le Z \le z)$ for $z \ge 0$ . To estimate $z$ from $P(Z \le z) = 0.6985$ , it would be necessary to find the appropriate

Since $P(Z \le z) = 0.6985$ and is greater than $P(Z \le 0) = 0.50$ , $z > 0$ . As a result, $P(Z \le z)$ can be written as the sum of $P(Z < 0)$ and $P(0 \le Z \le z)$ . Besides, $P(Z < 0) = P(Z \le 0) = 0.50$ . As a result:

$\begin{aligned}&P(Z \le z)\\ &= P(Z < 0) + P(0 \le Z \le z) \\ &= 0.50 + P(0 \le Z \le z)\end{aligned}$ .

Therefore:

$\begin{aligned}&P(0 \le Z \le z) \\ &= P(Z \le z) - 0.50 \\&= 0.6985 - 0.50 \\&=0.1985 \end{aligned}$ .

Lookup $0.1985$ on a normal distribution table. The corresponding $z$ -score is $0.52$ . (In other words, $P(0 \le Z \le 0.52) = 0.1985$ .)

Given that

$z = 0.52$ ,
$x =5$ , and
$\sigma = 2$ ,

Solve the equation $\displaystyle z = \frac{x - \mu}{\sigma}$ for the mean, $\mu$ :

$\displaystyle 0.52 = \frac{5 - \mu}{2}$ .

$\mu = 5 - 2 \times 0.52 = 3.96$ .

3 0

3 years ago

The question is in the photo

masha68 [24]

Step-by-step explanation:

I think the answer is 3x square multiplied by 1

Coz anything raised to power 0 will always equal to 1

8 0

3 years ago

Having trouble with this one can somebody help?

Varvara68 [4.7K]

Form equation
y = mx + c
y = (rise/run).x + c
y = (11-1 / 3--2)x + c
y = 2x + c
11 = 2(3) + c
Find c (y-intercept)
11 - 6 = c
c = 5
Final equation of line
y = 2x + 5
Substitute given possible x-values in to find y-values
y = 2(1) + 5 = 7 (1,7)
y = 2(2) + 5 = 9 (2,9)
Therefore d is correct

3 0

3 years ago

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Zina [86]

Answer:

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6 0

3 years ago