the answer is none of the above because the variable cant be combined and 56 cant either.
Answer:
See below, please!
Step-by-step explanation:
We can set up a system of equations to model this problem. Let's consider the student's ticket as x, and y for the adult ticket.
So since the student ticket is $1.50, and adult is $4, we can set up the following equation: 
, since they collected $5050 total.
We can set up another equation modeling the number of people who came to the game. This would be x+y=2200.
Solve this, and we get x= 1500 and y=700. So, they sold 1500 student tickets and 700 adult tickets.
Hope this helped!
As rolling a one on a fair die has a probability of 1/6, on average it is likely that a one will be rolled around once every six rolls, therefore the game’s expected value is 0 because in six rolls one roll will yield 50 and the other five rolls -10 each granting a net total of 0.
Answer:
Fernando incorrectly found the product of –2 and –5.
Step-by-step explanation:
Fernando evaluated the numerator of the fraction incorrectly.
Fernando simplified StartFraction 20 over 2 EndFraction incorrectly.
Fernando incorrectly found the product of –2 and –5.
Fernando evaluated (negative 3) squared incorrectly.
Fernando's calculation
5(9-5) / 2 + (-2)(-5) + (-3)^2
= 5(4) / 2 - 10 + 9
= 20/2 - 10 + 9
= 10 - 10 + 9
= 9
Correct calculation
5(9-5) / 2 + (-2)(-5) + (-3)^2
= 5(4) / 2 + (10) + 9
= 20/2 + 10 + 9
= 10 + 10 + 9
= 29
Therefore,
Fernando's error was multiplying (-2)(-5) to be equal to -10 instead of 10
Fernando incorrectly found the product of –2 and –5.
