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Mamont248 [21]
3 years ago
14

The radius of is circle is 3 kilometers. what is the length of a 180 arc?

Mathematics
1 answer:
NeX [460]3 years ago
8 0

Answer:

9.43km

Step-by-step explanation:

Length of an arc = 2πr(Ф/360)= 2 x 22/7 x 3 x (180/360)

2 x22/7 x 3 x 1/2 = 22/7 x 3 = 66/7 = 9.42857142857≈9.43

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What is the value of x in the equation log(x+2) - log(x-1) = log 2​
pentagon [3]

Step-by-step explanation:

log(x+2)-log(x-1)=log2

log(x+2)/(x-1)=log2

=> (x+2)=2(x-1)

=>x+2 =2x-2

=> x=4

5 0
3 years ago
Find the area of the shape shown<br> below.
steposvetlana [31]

Answer:

The area of the figure is 28 units².

Step-by-step explanation:

Find the area of the full rectangle, ignoring the triangle.

a = lw \\ a = 4 \times 8 = 32

Then, find the area of the triangle:

a =  \frac{bh}{2}  \\ a =  \frac{2 \times 4}{2}  \\ a = 4

Finally, subtract:

32 - 4 = 28

7 0
3 years ago
√(2x+1)<br> Evaluate the integral<br> 2<br> (2x + 1) In (2x + 1)<br> dx.
Crank

Substitute y=\ln(2x+1) and dy=\frac2{2x+1}\,dx, so that

\displaystyle \int \frac2{(2x+1) \ln(2x+1)} \, dx = \int \frac{dy}y = \ln|y| + C = \boxed{\ln|\ln(2x+1)| + C}

6 0
1 year ago
Gavin drank 4 5 liter of water Monday before going jogging. He drank 2 3 liter of water after his jog. How much water did Gavin
Hoochie [10]

Answer:

<h2>8.0 liters</h2>

Step-by-step explanation:

The question is not well-formatted, this is supposed to be the correct format

<em>Gavin drank 4.5 liter of water Monday before going jogging. He drank 2.3 liter of water after his jog. How much water did Gavin drink altogether? Write your answer as a mixed number.</em>

Given

we are told that he first drank 4.5 liters of water before jogging

after jogging he drank 2.3 liters

Required

Total amount of water drank

=4.5+3.5

=8.0liters

5 0
3 years ago
Which of the following are identities? Check all that apply
Natasha2012 [34]

Answer:

A, C

Step-by-step explanation:

Actually, those questions require us to develop those equations to derive into trigonometrical equations so that we can unveil them or not. Doing it only two alternatives, the other ones will not result in Trigonometrical Identities.

Examining

A) True

\frac{1-tan^{2}x}{2tanx} =\frac{1}{tan2x} \\ \frac{1-tan^{2}x}{2tanx} =\frac{1}{\frac{2tanx}{1-tan^{2}x}}\\ tan2x=\frac{1-tan^{2}x}{2tanx}

Double angle tan2\alpha =\frac{1 -tan^{2}\alpha }{2tan\alpha}

B) False,

No further development towards a Trig Identity

C) True

Double Angle Sine Formula sin2\alpha =2sin\alpha *cos\alpha

sin(8x)=2sin(4x)cos(4x)\\2sin(4x)cos(4x)=2sin(4x)cos(4x)

D) False No further development towards a Trig Identity

[sin(x)-cos(x)]^{2} =1+sin(2x)\\ sin^{2} (x)-2sin(x)cos(x)+cos^{2}x=1+2sinxcosx\\ \\sin^{2} (x)+cos^{2}x=1+4sin(x)cos(x)

7 0
3 years ago
Read 2 more answers
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