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levacccp [35]
3 years ago
15

I really need help with this pls help and show work​

Mathematics
1 answer:
ohaa [14]3 years ago
6 0

okay so first we need to multiply 160 on both sides

{18/32(160)=n/160*160 (160 cancels out)}

so once we finish our calculations on the left side we get n equals 90

{n=90}

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in the circl below, AD is diameter and AB is tangent at A. Suppose mADC=228*, find the measures of mCAB and mCAD. Type your nume
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Given:

AD is diameter of the circle, AB is the tangent, and measure of arc ADC is 228 degrees.

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The m\angle CAB and m\angle CAD.

Solution:

AD is diameter of the circle. So, the measure of arc AD is 180 degrees.

m(arcADC)=m(arcAD)+m(arcDC)

228^\circ=180^\circ+m(arcDC)

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m\angle BAD=m\angle CAB+m\angle CAD

90^\circ=m\angle CAB+24^\circ

90^\circ -24^\circ=m\angle CAB

66^\circ=m\angle CAB

Therefore, m\angle CAB=66^\circ and m\angle CAD=24^\circ.

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