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ElenaW [278]
3 years ago
6

identify the equation that does not belong with the other three. explain your reasoning. 6+x=9 | 15= x+12 | x+9 =11 | 7+x=10

Mathematics
1 answer:
Katena32 [7]3 years ago
6 0
Answer is x+9=11

6+x=9
x=3

15=x+12
x=3

7+x=10
x=3

x+9=11
x=2

So x+9=11 has a different x value than the rest of the equations. So it doesn't belong with the other three.
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Given that f(x) = 2x + 9, find the value that makes f(x) = 27.
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Answer:

9

Step-by-step explanation:

f(x) = 2x+9

f(x) = 27

so, you get:

2x+9=27

2x=18

x=9

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Help please (will chose brainliest).
lara [203]
Answers with Explanation.


i. If we raise a number to an exponent of 1, we get the same number.

{10}^{1}  = 10

ii. If we raise 10 to an exponent of 2, it means we multiply 10 by itself two times.

{10}^{2}  = 10 \times 10 = 100

iii. If we raise 10 to an exponent of 3, it means we multiply 10 by itself three times.



{10}^{3}  = 10 \times  {10}^{2}  = 10 \times 100 = 1000

iv. If we raise 10 to an exponent of 4, it means we multiply 10 by itself four times.


{10}^{4}  =  10 \times {10}^{3} = 10 \times 1000 =  10000

v. If we raise 10 to an exponent of 5, it means we multiply 10 by itself five times.



{10}^{5}  = 10 \times  {10}^{4}  = 10 \times 10000 = 100000

{10}^{5}  = 100000

vi. Recall that,

{a}^{ - m}  =  \frac{1}{ {a}^{m} }
We apply this law of exponents to obtain,

{10}^{ - 2}  =  \frac{1}{{10}^{2} }  =  \frac{1}{100}

vii. We apply
{a}^{ - m}  =  \frac{1}{ {a}^{m} }
again to obtain,


{10}^{ - 3}  =  \frac{1}{ {10}^{3} }  =  \frac{1}{1000}





5 0
3 years ago
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