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avanturin [10]
3 years ago
11

(08.01, 08.02, 08.03, 08.05, 08.06 MC)

Mathematics
2 answers:
fenix001 [56]3 years ago
6 0
Is it x times 2 times y times 2? is that what it is asking or is it meaning squared
zhannawk [14.2K]3 years ago
3 0

Answer: The factorization of all the parts are :

Part A : x^2y^2+6xy^2+8y^2=y^2(x+2)(x+4).

Part B :  x^2+8x+16=(x+4)(x+4).

Part C :  x^2-16=(x+4)(x-4).

Step-by-step explanation:  We are given to factorize the following quadratic polynomials :

Part A : Factor x²y² + 6xy² + 8y².  

Part B : Factor x² + 8x + 16.

Part C: Factor x² − 16.

We will be using the following factorization formulas :

(i)~x^2+ax+bx+ab=(x+a)(x+b),\\\\(ii)~x^2+2xa+a^2=(x+a)^2=(x+a)(x+a),\\\\(iii)~x^2-a^2=(x+a)(x-a).

The factorization of all the parts area as follows :

<u><em>Part A :</em></u>

We have

x^2y^2+6xy^2+8y^2\\\\=y^2(x^2+6x+8)\\\\=y^2(x^2+4x+2x+8)\\\\=y^2(x(x+4)+2(x+4))\\\\=y^2(x+2)(x+4).

So, x^2y^2+6xy^2+8y^2=y^2(x+2)(x+4).

<u><em>Part B : </em></u>

We have

x^2+8x+16\\\\=x^2+2\times x\times4+4^2\\\\=(x+4)^2\\\\=(x+4)(x+4).

So, x^2+8x+16=(x+4)(x+4).

<u><em>Part C :</em></u>

We have

x^2-16\\\\=x^2-4^2\\\\=(x+4)(x-4).

So, x^2-16=(x+4)(x-4).

Thus, all the parts are factorized.

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