2h - 7h + 2h2 - h+ 6 + 4h9h

Dima020 [189]

Answer:

$=-1\frac{1}{2}$

Step-by-step explanation:

Given the following question:

$-3\frac{3}{4} \div2\frac{1}{2}$

In order to find the answer, we first convert the mixed numbers into improper fractions. Then we use KCF (Keep, Change, Flip) and solve.

$-3\frac{3}{4} \div2\frac{1}{2}$
$-3\frac{3}{4} =12+3=-\frac{15}{4}$
$2\frac{1}{2}=2\times2=4+1=\frac{5}{2}$
$-\frac{15}{4} \div\frac{5}{2}$
$-\frac{15}{4} \times\frac{2}{5}$
$15\times2=30$
$4\times5=20$
$=-\frac{30}{20}$
$-\frac{30}{20} \div10=-\frac{3}{2}$
$-\frac{3}{2}=3\div2=-1\frac{1}{2}$
$=-1\frac{1}{2}$

Hope this helps.

4 0

2 years ago

Hi! Can I please have some help and can you please show me how you got your answer? thank you!

Mama L [17]

Answer: -5z+13
Step by step:
6z-5
-z-8 now you add -5, and -8 and it becomes positive. And then you subtract 6z and -z
You get -5z+13

5 0

3 years ago

Evaluate the following: 18 + 3 |6 - 25| - 11

Advocard [28]

Answer:

29 (Unless I'm mistaken)

Step-by-step explanation:

18+3|6-25|-11

21+19-11

29

6 0

4 years ago

A manufacturer of bicycles has determined that 550 bikes per month will be sold at a price of $250. At a price of $150, it is es

iogann1982 [59]

750 bikes would be sold for $350

Let x represent the number of bikes sold per month and y represent the price.

550 bikes are sold at a price of $250, this can be represented by (550, 250). Also, 750 bikes is sold at a price of $150, hence it is represented by (750, 150)

A linear function is represented by:

y = mx + b

m is the slope, b is the y intercept.

Therefore the function is:

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\y-250=\frac{150-250}{750-550} (x-550)\\\\y=\frac{1}{2}x-25$

The number of bikes sold for $350 is:

350 = (1/2)x - 25

x = 750

Therefore 750 bikes would be sold for $350

Find out more at: brainly.com/question/13911928

3 0

3 years ago

What are the coordinates of the vertices of the pre-image given? ry= −x ◦ T1, −2(x, y)

nataly862011 [7]

<h3><u>Answer:</u></h3>

Hence, the coordinates of pre-image are:

A(1,6) , B(0,4) , C(3,4) , D(2,6)

<h3><u>Step-by-step explanation:</u></h3>

We have to find the coordinates of the vertices of the pre-image given?

Ry= −x ◦ T_1, −2(x, y)

i.e. we have to find the composition of reflection along the line y=-x and translation with the rule:

(x,y) → (x+1,y-2)

Now we have coordinates of A",B",C" and D" as:

A"(-4,-2)

B"(-2,-1)

C"(-2,-4)

D"(-4,-3)

Now we are asked to find the coordinates of the pre-image.

Also when any point is reflected along y=-x then the point is transformed to:

(x,y) → (-y,-x)

Let A,B,C and D are the points of the pre-image.

Hence, the coordinates of the pre-image are given as:

so, the transformation is given as:

A→A'→A"

B→B'→B"

C→C'→C"

D→D'→D"

Where A',B',C',D' represents the transformation after translation and A",B",C",D" represents the transformation after reflection as well.

The coordinates of A' are (2,4)

B' are (1,2)

C' are (4,2)

and D' are (3,4)

Now, the coordinates of pre-image are given as:

A'(x,y) → A(x-1,y+2)=A(1,6)

B'(x,y) → B(x-1,y+2)=B(0,4)

C'(x,y) → C(x-1,y+2)=C(3,4)

and D'(x,y) → D(x-1,y+2)=D(2,6)

Hence, the coordinates of pre-image are:

A(1,6) , B(0,4) , C(3,4) , D(2,6)

4 0

3 years ago

2h - 7h + 2h2 - h+ 6 + 4h9h​

2h - 7h + 2h2 - h+ 6 + 4h9h