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2 years ago

Consider the function f(x) = 5x - 5+1

Mathematics

1 answer:

swat322 years ago

4 0

Answer: D: 5x-5>0

Step-by-step explanation:

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What is 6.685 rounded to the nearest hundredths place

loris [4]

Answer:

6.69

Step-by-step explanation:

The hundredths place is two decimal places to the right. This lands you at 8, so you must look at the number after it to determine whether you round up or down. So you look at 5, which rounds the 8 up to 9. Therefore, it is 6.69

7 0

3 years ago

Read 2 more answers

Expression related to -1/3(6x+15)-3

marshall27 [118]

Answer:

x = -4 and -2x - 8

Step-by-step explanation:

<u>Step 1: Distribute</u>

-1/3(6x + 15) - 3

-6/3x - 15/3 - 3

-2x - 5 - 3

-2x - 8

<u>Step 2: IF NEEDED SOLVE FOR X</u>

-2x - 8 + 8 = 0 + 8

-2x / -2 = 8 / -2

x = -4

Answer: x = -4 and -2x - 8

5 0

2 years ago

How do i find x and y?

mario62 [17]

Answer:

y=65

x=50

Step-by-step explanation:

exterior angle of a triamgle is equal to sum of two interior angles

2y=130(as it is isosceles triangle)

y=65

we know y+y+x=180(sum of all angles of triangle)and (vertically opposite angle)

therefore, x=50

8 0

3 years ago

Read 2 more answers

What is the Answer to this problem 75x+2=

pashok25 [27]

75x+2=
75x-2=-2. move the 2 to the other side
75x=-2 now divide 75 both sides

75/75x=-2/75
x=-2/75

4 0

2 years ago

A supplier delivers an order for 20 electric toothbrushes to a store. By accident, three of the electric toothbrushes are defect

Vladimir79 [104]

The probability that the first two electric toothbrushes sold are defective is 0.016.

The probability of an event, say E occurring is:

$P(E)=\frac{n(E)}{N}$

Here,

n (E) = favorable outcomes

N = total number of outcomes

Let X = the number of defective electric toothbrushes sold.

The number of electric toothbrushes that were delivered to a store is n = 20.

The number of defective electric toothbrushes is x = 3.

The number of ways to select two toothbrushes to sell from the 20 toothbrushes is:

$(\left {{20} \atop {2}} \right. )$ $=\frac{20!}{2!(20-2)!} =\frac{20!}{2!18!} =\frac{20*19*18!}{2!*18!} = 190$

The number of ways to select two defective toothbrushes to sell from the 3 defective toothbrushes is:

$(\left {{3} \atop {2}} \right. )$ $=\frac{3!}{2!(3-2)!} =\frac{3!}{2!1!} =\frac{3*2!}{1!2!} =3$

Compute the probability that the first two electric toothbrushes sold are defective as follows:

P (Selling 2 defective toothbrushes) = Favorable outcomes ÷ Total no. of outcomes

$\frac{3}{190}\\ =0.01579\\=0.016$

Thus, the probability that the first two electric toothbrushes sold are defective is 0.016.

Learn more about probability here brainly.com/question/27474070

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4 0

1 year ago