M∠2=(y+52)∘and m∠7=(2y+17)∘ . What is the value of y?
1 answer:
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Answer:
Complete Question:
Pick a city in Maryland and determine the average high temperatures for each month. Record this in a table.
a. Create a box-and-whisker plot for the data.
b. What is the median temperature?
c. 75%of the temperatures are below what value?How do you know? d. 75% of the temperatures are above what value? How do you know? e. What conclusions can you draw about the temperature in Maryland?
Step-by-step explanation:
TASK 3
The city picked is Baltimore, the year 2017.
The table is attached in picture #1.
a) The box-and-whisker plot is attached in picture #2.
b) The median is the central value of the distribution i.e:
42.4, 45.3, 46.8 | 54.7, 57.6, 66.0 | 69.1, 76.5, 80.6 | 85.8, 87.8, 90.0
where we marked with a tally the quartiles.
As we have 12 values, the average between the two central values will be the median :
M = (66.0 + 69.1) / 2 = 67.1 °F
c) 75% of the temperatures are below 83.2 °F.
Indeed, this value represents the third quartile. The position of the third quartile can be found by the formula:
3/4 · (n + 1) = 3/4 · (12 + 1) = 3/4 · 13 = 9.75
Therefore, since we did not get in integer position, the third quartile will be the average between the numbers in position 9 and 10:
q₀.₇₅ = (80.6 + 85.8) / 2 = 83.2 °F
d) 75% of the temperatures are above 50.8 °F.
Indeed, this value represents the first quartile. Similarly to point c), the position can be found by the formula:
1/4 · (n + 1) = 1/4 · 13 = 3.25
And therefore:
q₀.₂₅ = (46.8 + 54.7) / 2 = 50.8 °F.
e) Baltimore in 2017 had a median high temperature of 67.1 °F.
25% of the year the high temperatures were warmer than 83.2 °F, with no outlier above 90.0 °F which was the hottest temperature.
25% of the high temperatures were colder than 50.8 °F, with no outlier below 42.4 °F, which was the coldest high temperature.
Answer:
a). The mean = 1000
The variance = 999,000
The standard deviation = 999.4999
b). 1000 times , loss
Step-by-step explanation:
The mean of geometric distribution is given as ,
And the variance is given by,
Given :
= 0.001
The formulae of mean and variance are :
a). Mean =
=
= 1000
Variance =
=
= 999,000
The standard deviation is determined by the root of the variance.
= = 999.4999
b). We expect to have play lottery 1000 times to win, because the mean in part (a) is 1000.
When we win the profit is 500 - 1 = 499
When we lose, the profit is -1
Expected value of the mean μ is the summation of a product of each of the possibility x with the probability P(x).
= $ 0.50
Since the answer is negative, we are expected to make a loss.