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Harlamova29_29 [7]
3 years ago
12

You are downloading a song. The percent y(in decimal form) of megabytes remaining to download after x seconds is y=-0.1x+1.

Mathematics
2 answers:
Xelga [282]3 years ago
5 0
The Y intercept is always when X equals 0. The X intercept is when Y equals 0.
An easy way to find x and y intercepts is to substitute these variables with 0.
To find the Y intercept, substitute 0 for X.
Y=-.1(0)+1=1 So you know that when Y equals 1 and X equals 0, you have you Y intercept.
Because we write coordinates as (X,Y), you can just plug in the numerals and have your coordinate for the Y intercept. So, x=0 y=1 (0,1)
To find the X intercept, substitute 0 for Y.
     0=-.1x+1 -Add .1x to both sides
+.1x   +.1x
   .1x=1       -Divide both side to get x by itself.
.1x/.1=1/.1
x=10   So, we know that when y=0, x=10. This is our x intercept.
Coordinate form is (X,Y) so our x intercept is (10,0)
igomit [66]3 years ago
3 0


I would make the equation have both of your variables on the same side:

0.1x+y=1

Then I would use the cover-up method and say that

x-intercept= 10

y-intercept= 1


*Cover-Up Method: If you were finding the X-intercept, you would just ignore the y variable and divide your whole number by x.

In this case the whole number is 1. 1/0.1=10

Vice Versa with finding the Y-intercept

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Read 2 more answers
Una caja de 25 newtons se suspende mediante un cable con diámetro de 2cm¿cuál es el esfuerzo aplicado al cable?
Naddik [55]

El cable experimenta un esfuerzo axial de 79577.472 pascales por el peso de la caja.

<h3>¿Cómo calcular el esfuerzo aplicado sobre el cable?</h3>

La caja tiene masa y está sometida a un campo gravitacional, por tanto, tiene un peso (W), en newtons. Por el principio de acción y reacción (tercera ley de Newton), encontramos que el cable es tensionado debido a ese peso y su área transversal experimenta un esfuerzo axial (σ), en pascales.

Asumiendo una distribución uniforme de la fuerza sobre toda la superficie transversal de la cuerda, tenemos que el esfuerzo axial se calcula mediante la siguiente expresión:

σ = W / (π · D² / 4)

Donde:

  • W - Peso de la caja, en newtons.
  • D - Diámetro del área transversal de la caja, en metros.

Si sabemos que W = 25 N y D = 0.02 m, entonces el esfuerzo axial aplicado a la cuerda es:

σ = 25 N / [π · (0.02 m)² / 4]

σ ≈ 79577.472 Pa

<h3>Observación</h3>

La falta de problemas verificados en español sobre esfuerzos axiales obliga a buscar uno equivalente en inglés.

Para aprender más sobre esfuerzos axiales: brainly.com/question/13683145

#SPJ1

5 0
1 year ago
Please answer with steps thank you :)
mart [117]
200×180 =36,000
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3 years ago
Which if the following items showed the greatest percentage in bulk
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No image shown but just remember that percentage is out of 100

0.03 is 3%
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3 years ago
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