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2 years ago

12

(2x^3-7x^2-16x-6)÷(2x+1)

1 answer:

Akimi4 [234]2 years ago

8 0

1.236293992929299292929

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Can somebody help me with (a) and (b)? Thanks! :D

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3 years ago

If g(x)=4x-6 then g^-1(x)=?<br> (1) -4x+6<br> (2)-1/4x+1/6<br> (3)1/4x+3/2<br> (4)1/4x+6

kati45 [8]

Given:

$g(x)=4x-6$

To find:

The function $g^{-1}(x)$ .

Solution:

we have,

$g(x)=4x-6$

Put g(x)=y.

$y=4x-6$

Interchange x and y.

$x=4y-6$

Isolate y.

$x+6=4y$

$\dfrac{x+6}{4}=y$

$y=\dfrac{x+6}{4}$

Substitute $y=g^{-1}(x)$ .

$g^{-1}(x)=\dfrac{x+6}{4}$

$g^{-1}(x)=\dfrac{x}{4}+\dfrac{6}{4}$

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3 years ago

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anyanavicka [17]

Answer:

bruh

Step-by-step explanation:

maybe google works

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