Help please thank you!

Please help !Suppose that the height in centimeters of a candle is a linear function of them out of time in hours it has been bu

Elan Coil [88]

Answer:

17.8 cm

Step-by-step explanation:

In the 17 hours between heights of 18.6 cm and 15.2 cm, the candle lost 3.4 cm in height. That is, the height decreased at the rate of ...

(-3.4 cm)/(17 h) = -0.2 cm/h

In the 4 hours between 12 hours and 16 hours of burning time, the candle will have changed its height by (4 h)(-0.2 cm/h) = -0.8 cm.

The height at 16 hours of burning is then 18.6 cm -0.8 cm = 17.8 cm.

4 0

3 years ago

Geometry hw!!! picture is above

AnnZ [28]

X=12 because 73-3x=61-2x so add 3x to both to make 73=61+X then subtract 61 from both to get 12=X

7 0

2 years ago

1/10 of ______ is 10 times as much as 8

koban [17]

The answer is 800.
To find this, multiply 10 times 8 to find the number you are dividing. (80) now, multiply 80 by 10. (800)
1/10 of 800 is 80, which is ten times as much as 8.

3 0

3 years ago

8) can u answer this question pls

Vsevolod [243]

Answer: 346.19cm²

Step-by-step explanation:

π= 3.14

Divide 21 (the diameter) by 2 to get the radius( it 's half of the diameter). so the radius is 10.5

Area= πr²

= 3.14x10.5x10.5

= 346.185

So next round up the value you got to the nearest tenth, so when u round up to the nearest tenth you get 346.19

3 0

1 year ago

Part B

Troyanec [42]

Answer:

Part A) The length of a straight line between the school and the Fire Station is $4.6\ miles$

Part B) The length of a straight line between the school and the hospital is $2.1\ miles$

Step-by-step explanation:

<u><em>The complete question in the attached figure</em></u>

Let

The positive x-coordinates ----> East

The positive y-coordinates ----> North

The negative x-coordinates ----> West

The negative y-coordinates ----> South

take the point A (0,0) as the Middle School (reference point)

Part A) we have

Town Hall is located 4.3 miles directly east of the Middle School

so

The coordinates of Town Hall are B(4.3,0)

The Fire Station is located 1.7 miles directly North of Town Hall

so

The coordinates of Fire Station are C(4.3,1.7)

What is the length of a straight line between the school and the Fire Station?

Remember that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

A(0,0) and C(4.3,1.7)

substitute

$d=\sqrt{(1.7-0)^{2}+(4.3-0)^{2}}$

$d=\sqrt{(1.7)^{2}+(4.3)^{2}}$

$d=4.6\ miles$

Part B) we have that

The hospital is 3.1 miles west of the fire station

so

The coordinates of the hospital are D(4.3-3.1,1.7)

D(1.2,1.7)

What is the length of a straight line between the school and the hospital?

Remember that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

A(0,0) and D(1.2,1.7)

substitute

$d=\sqrt{(1.7-0)^{2}+(1.2-0)^{2}}$

$d=\sqrt{(1.7)^{2}+(1.2)^{2}}$

$d=2.1\ miles$

7 0

3 years ago