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DENIUS [597]
3 years ago
8

Which expression is equivalent to the following complex fraction? StartFraction 1 Over x EndFraction minus StartFraction 1 Over

y EndFraction divided by StartFraction 1 Over x EndFraction + StartFraction 1 Over y EndFraction
Mathematics
2 answers:
Darina [25.2K]3 years ago
6 0

Answer:

\frac{y-x}{x+y}

Step-by-step explanation:

We are given that fraction

\frac{\frac{1}{x}-\frac{1}{y}}{\frac{1}{x}+\frac{1}{y}}

We have to find the expression which is equivalent to given  fraction .

\frac{1}{x}-\frac{1}{y}=\frac{y-x}{xy}

\frac{1}{x}+\frac{1}{y}=\frac{x+y}{xy}

Substitute the values  then, we get

\frac{\frac{y-x}{xy}}{\frac{y+x}{xy}}

We know that

\frac{\frac{a}{b}}{\frac{x}{y}}=\frac{a}{b}\times \frac{y}{x}

Using the property then, we get

\frac{y-x}{xy}\times \frac{xy}{x+y}

\frac{y-x}{x+y}

This is required expression which is equivalent to given expression.

avanturin [10]3 years ago
6 0

Answer: It’s D

Step-by-step explanation:

Took quiz on edge

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Ulleksa [173]

Answer:

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The mean is given by:

\mu = 3.8+2.9= 6.7

And the standard deviation would be:

\sigma =\sqrt{1.2^2 + 1.7^2} = 2.08

And the distribution for X+Y would be:

X+Y \sim N(6.7 , 2.08)

And the best answer would be:

D.) Mean, 6.7; standard deviation, 2.08

Step-by-step explanation:

Let X the random variable who represent the AP Art History exam we know that the distribution for X is given by:

X \sim N(3.8, 1.2)

Let Y the random variable who represent the AP English exam we know that the distribution for X is given by:

X \sim N(2.9, 1.7)

We want to find the distribution for X+Y. Assuming independence between the two distributions we have:

X+Y \sim N(\mu_X +\mu_Y , \sqrt{\sigma^2_X +\sigma^2_Y})

The mean is given by:

\mu = 3.8+2.9= 6.7

And the standard deviation would be:

\sigma =\sqrt{1.2^2 + 1.7^2} = 2.08

And the distribution for X+Y would be:

X+Y \sim N(6.7 , 2.08)

And the best answer would be:

D.) Mean, 6.7; standard deviation, 2.08

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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