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Fynjy0 [20]
3 years ago
8

PLS HELP ASAP!!! domain & range of g(x)?

Mathematics
1 answer:
Morgarella [4.7K]3 years ago
6 0
Domain: (-infinity, +infinity)
range: (0, +infinity)
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A right triangle has a leg of 11 cm and a hypotenuse of 17 cm.
Vedmedyk [2.9K]
The answer would be the second option, 13.0 cm.

To find the missing length of the leg, you would use the pythagorean theorem and substitute your inputs in.

a^2+b^2=c^2
11^2+b^2=17^2
121+b^2=289
b^2=168
b=12.96 
b=13.0 cm (rounded up)
4 0
3 years ago
Read 2 more answers
your gym membership cost $33 per month after an initial membership fee. you paid a total of $228 after 6 months. writer an equat
grin007 [14]

Answer:

what i did was multiply 33*6 and got 198 and then 228-198 to find out that the initial fee was 30 dollars. then multiply 33*9+30 to get a  9-month total cost of $327

Step-by-step explanation:

cost = $33 per month + fee  

1.  c(m) = 33m + f

 33(6) + f = 228

198 + f = 228

f = $30 membership fee  

c(m) = 33m + 30

 2.  at 9 months:  33(9) + 30 = $327

hopefully this helps :)

have a nice day !!

7 0
3 years ago
Can a triangle have sides with the given lengths 8cm, 7cm, 9cm explain
erik [133]

Answer:

yes.

Step-by-step explanation:

i forgot the name of the triangle

8 0
3 years ago
What is the slope of a perpendicular line through -y=-2x+8?
tia_tia [17]
I think it is b hope it’s write
6 0
3 years ago
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Write square root of 64 - square root of -289 as a complex number in the form of a+bi
stellarik [79]

Answer:

\sqrt{64}-\sqrt{-289}

=8-17i

Step-by-step explanation:

\sqrt{64}=8 because 8(8)=64 and 8 is the positive square root of 64.

\sqrt{-289}=17i because 17i(17i)=289i^2=-289(-1)=-289.

\sqrt{64}-\sqrt{-289}

8-17i

8 0
3 years ago
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