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3 years ago

I want the answer to this , zoom in if you can't see well

Mathematics

1 answer:

galben [10]3 years ago

3 0

We are going to need to know the formula for the lateral surface area and volume of a cylinder in order to find our answers. Below are the equations:

$A_L = 2 \pi r h$

$V = \pi r^2 h$

$h$ is the height
$r$ is the radius

Using these formulas, we can solve these problems.

$A_L = 2 (3.14)(48.9) (84.3) \approx \boxed{25887.856}$

$V = (3.14) (48.9)^2 (84.3) \approx \boxed{632958.069}$

You might be interested in

If AC = 24, find the value of x. Then find AB and BC

anzhelika [568]

Answer:

The answer is below

Step-by-step explanation:

The question is not complete, the correct question is:

If B is between A and C, and AB=3x+1, BC=2x-7, and AC=24, then find the value of x and the value of AB

Answer: The line segment addition postulate states that if a point B is placed between a line segment with end points A and C, then the distance between the points can be expressed by the equation:

AB + BC = AC

But AB=3x+1, BC=2x-7, and AC=24, Hence:

3x + 1 + 2x - 7 = 24

3x + 2x + 1 - 7 = 24

5x - 6 = 24

5x = 24 + 6

5x = 30

x = 6

AB = 3x + 1 = 3(6) + 1 = 18 + 1 = 19

BC = 2x - 7 = 2(6) - 7 = 12 - 7 = 5

5 0

3 years ago

Flow meters are installed in urban sewer systems to measure the flows through the pipes. In dry weatherconditions (no rain) the

ziro4ka [17]

Answer:

a) $\frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}$

$363.90 \leq \sigma^2 \leq 4430.80$

Now we just take square root on both sides of the interval and we got:

$19.08 \leq \sigma \leq 66.56$

b) For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

Step-by-step explanation:

423.6, 487.3, 453.2, 402.9, 483.0, 477.7, 442.3, 418.4, 459.0

Part a

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

On this case we need to find the sample standard deviation with the following formula:

$s=sqrt{\frac{\sum_{i=1}^8 (x_i -\bar x)^2}{n-1}}
And in order to find the sample mean we just need to use this formula:
[tex]\bar x =\frac{\sum_{i=1}^n x_i}{n}$

The sample deviation for this case is s=30.23

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

$df=n-1=9-1=8$

The Confidence interval is 0.98 or 98%, the value of $\alpha=0.02$ and $\alpha/2 =0.01$ , and the critical values are:

$\chi^2_{\alpha/2}=20.09$

$\chi^2_{1- \alpha/2}=1.65$

And replacing into the formula for the interval we got:

$\frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}$

$363.90 \leq \sigma^2 \leq 4430.80$

Now we just take square root on both sides of the interval and we got:

$19.08 \leq \sigma \leq 66.56$

Part b

For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

4 0

3 years ago

10 to the 0 power =what pattern

Citrus2011 [14]

Any number to the power 0 is 1.

So 10^0 = 1

3 0

3 years ago

What is the value of B - A as a fraction?

umka21 [38]

Answer:
A = 1/4
B = 3/4

step-by-step explanation:
the middle should be 1/2 because the middle between 0 and 1 is 1/2
A and B are both in the middle of the sides
therefore A would be closer to 0 so 1/4
and B would be closer to 1 so 3/4

6 0

3 years ago

The royals softball team played 75 games and won 55 of them. What percent of the games did they lose (round to the nearest hundr

dimaraw [331]

If they won 55 of the games, that means they lost the rest of the 75. So,
75 - 55 = 20 games lost. To find the percentage of 20 out of 75, you set up a proportion:

$\frac{20}{75}=\frac{x}{100}$

where x = the percentage of games lost. Cross multiply and divide to isolate the x:

$\frac{20}{75}=\frac{x}{100}\\75x=2000\\75x/75=2000/75\\x=26.6666667$

Rounded to the nearest hundredth, the Royals lost 26.667 % of their games.

3 0

3 years ago

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