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Zina [86]
3 years ago
14

The graph represents the normal distribution of recorded weights, in pounds, of cats at a veterinary clinic.

Mathematics
2 answers:
diamong [38]3 years ago
3 0

Answer:

<em>B)</em><em> 8.9 lbs </em>

<em>C)</em><em> 9.5 lbs </em>

<em>D)</em><em> 9.8 lbs </em>

<em>E)</em><em> 10.4 lbs</em>

Step-by-step explanation:

From the graph, 9.5 is the mean of the sample and 0.5 is the standard deviation of the sample.

As we have to find the weights that lie within the 2 standard deviations of the mean i.e

=9.5\pm 2(0.5)

=8.5,10.5

Among the given weights only 8.9 lbs, 9.5 lbs, 9.8 lbs, 10.4 lbs will lie within 2 standard deviations of the mean.


anyanavicka [17]3 years ago
3 0

Answer:

B

C

D

E

Step-by-step explanation:

8.9

9.5

9.8

10.4

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Solve the following sysyem of equations by the substitution method.  5x+y=8<br> 3×+y=8
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5x+y=8\\&#10;3x+y=8\\\\&#10;y=-5x+8\\&#10;3x+y=8\\\\&#10;3x-5x+8=8\\&#10;-2x=0\\&#10;x=0\\\\&#10;y=-5\cdot0+8\\&#10;y=8\\\\&#10;\boxed{(x,y)=(0,8)}
6 0
3 years ago
Solve for V.<br> 3y=39<br> Simplify your answer as much as possible.
Crank

Answer:

3y=39 :3

y=13

Step-by-step explanation:

prove me wrong

3 0
3 years ago
gde Sta manut Stree and Lincoln Set orm a right triangle with a trafic light at each intersection. The distance between the traf
earnstyle [38]

The diagram is of a right triangle with

Hypotenuse = 233

One leg of the triangle = 105

Another Leg = <em>we have to find</em>

<em />

<em />

Pythagorean Theorem can be written as:

\text{Leg}^2+\text{AnotherLeg}^2=\text{Hypotenuse}^2

Thus, we can write:

\begin{gathered} 105^2+\text{AnotherLeg}^2=233^2 \\ \text{AnotherLeg}^2=233^2-105^2 \\ \text{AnotherLeg}^2=43264 \\ \text{AnotherLeg}=\sqrt[]{43264} \\ \text{AnotherLeg}=208\text{ ft} \end{gathered}

Thus,

The distance between the traffic lights on Walnut Street is:

208 feet
4 0
1 year ago
Juan ran of a mile 2/5 every 4/7 of an hour. Find Juan’s rate in miles per hour
AfilCa [17]

Answer:

Juan runs 7/10 of a mile every hour

Step-by-step explanation:

First find out how much he ran every 1/7 of an hour

2/5 x 1/4 = 4/7 x 1/4

1/10 = 1/7

1/10 x 7 = 1/7 x 7

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8 0
3 years ago
A local business has an area reserved behind the store for a parking lot that is 78 meters long by 19 meters wide. The stalls of
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The total area available for cars to park will be 858m².

<h3>How to calculate the area?</h3>

The area of the parking lot will be:

= 78 × 19

= 1482m²

The area of aisle will be:

= 8 × 78

= 624m²

The available area will be:

= 1482m² - 624m²

= 858m².

The compact parking spaces that will fit in the lot will be:

N × 12.5 = 858

N = 858/12.5

N = 68

The non compact parking spaces that will fit in the lot will be:

N × 16.5 = 858

N = 858/16.5

N = 52

Learn more about area on:

brainly.com/question/7438648

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5 0
2 years ago
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