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3 years ago

Nnnn hnknbghvbytvbnyufvbyggyftctfcvtdc

Mathematics

2 answers:

zlopas [31]3 years ago

7 0

Answer:

thx

Step-by-step explanation:

aliya0001 [1]3 years ago

4 0

77 is the answer because hnkn+nnnn= 55 so u add 22 and that is 77

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A cooler contains eleven bottles of sports drink: five lemon-line flavored and six orange flavored. You randomly grab a bottle a

Elenna [48]

Answer:

The probability that you would choose lemon-lime and then orange is 3/11 =.273.

Step-by-step explanation:

These are 'dependent events', which mean that your the event is affected by previous events. So, because you have eleven total bottles (five lemon-lime and six orange) and you do not replace the first bottle, that would only leave you with ten bottles remaining. The probability that you will pick the lemon-lime on the first choice is 5/11 because all of the bottles are there. However, your second choice will only include ten total bottles since you already took one. The probability that you would choose orange would be 6/10. When you multiply these two fractions and reduce to simplest form, you get 3/11.

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3 years ago

The vertices of a triangle are A (-2, 2), B (4,10), and C (0, -2). Find the equation of the line that contains

Tpy6a [65]

Answer:

y = 1/2 x + 3

Step-by-step explanation:

mid point of line BC = (2, 4)

slope of the line containing median (m) = 1/2

y intercept (b)= 3

since y = mx + b

y = 1/2x + 3

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3 years ago

What is the area and perimeter for 107 cm

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it would be 15 in 2

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Douring a recent snowstorm, John measured the total snowfall accumulated at the end of each hour. He recorded his results in the

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3 years ago

(1) (10 points) Find the characteristic polynomial of A (2) (5 points) Find all eigenvalues of A. You are allowed to use your ca

Yuri [45]

Answer:

Step-by-step explanation:

Since this question is lacking the matrix A, we will solve the question with the matrix

$\left[\begin{matrix}4 & -2 \\ 1 & 1 \end{matrix}\right]$

so we can illustrate how to solve the problem step by step.

a) The characteristic polynomial is defined by the equation $det(A-\lambdaI)=0$ where I is the identity matrix of appropiate size and lambda is a variable to be solved. In our case,

$\left|\left[\begin{matrix}4-\lamda & -2 \\ 1 & 1-\lambda \end{matrix}\right]\right|= 0 = (4-\lambda)(1-\lambda)+2 = \lambda^2-5\lambda+4+2 = \lambda^2-5\lambda+6$

So the characteristic polynomial is $\lambda^2-5\lambda+6=0$ .

b) The eigenvalues of the matrix are the roots of the characteristic polynomial. Note that

$\lambda^2-5\lambda+6=(\lambda-3)(\lambda-2) =0$

So $\lambda=3, \lambda=2$

c) To find the bases of each eigenspace, we replace the value of lambda and solve the homogeneus system(equalized to zero) of the resultant matrix. We will illustrate the process with one eigen value and the other one is left as an exercise.

If $\lambda=3$ we get the following matrix

$\left[\begin{matrix}1 & -2 \\ 1 & -2 \end{matrix}\right]$ .

Since both rows are equal, we have the equation

$x-2y=0$ . Thus x=2y. In this case, we get to choose y freely, so let's take y=1. Then x=2. So, the eigenvector that is a base for the eigenspace associated to the eigenvalue 3 is the vector (2,1)

For the case $\lambda=2$ , using the same process, we get the vector (1,1).

d) By definition, to diagonalize a matrix A is to find a diagonal matrix D and a matrix P such that $A=PDP^{-1}$ . We can construct matrix D and P by choosing the eigenvalues as the diagonal of matrix D. So, if we pick the eigen value 3 in the first column of D, we must put the correspondent eigenvector (2,1) in the first column of P. In this case, the matrices that we get are

$P=\left[\begin{matrix}2&1 \\ 1 & 1 \end{matrix}\right], D=\left[\begin{matrix}3&0 \\ 0 & 2 \end{matrix}\right]$

This matrices are not unique, since they depend on the order in which we arrange the eigenvalues in the matrix D. Another pair or matrices that diagonalize A is

$P=\left[\begin{matrix}1&2 \\ 1 & 1 \end{matrix}\right], D=\left[\begin{matrix}2&0 \\ 0 & 3 \end{matrix}\right]$

which is obtained by interchanging the eigenvalues on the diagonal and their respective eigenvectors

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3 years ago