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Mariana [72]
3 years ago
15

A variety of two types of snack packs are delivered to a store. The box plots compare the number of calories in each snack pack

of crackers to the number of calories in each snack pack of trail mix. A number line goes from 65 to 115. Crackers's whiskers range from 70 to 100, and the box ranges from 75 to 85. A line divides the box at 80. Cookies's whiskers range from 70 to 115, and the box ranges from 90 to 105. A line divides the box at 100. Which statement is true about the box plots? The interquartile range of the trail mix data is greater than the range of the cracker data. The value 70 is an outlier in the trail mix data. The upper quartile of the trail mix data is equal to the maximum value of the cracker data. The number of calories in the packs of trail mix have a greater variation than the number of calories in the packs of crackers.
Mathematics
2 answers:
Anika [276]3 years ago
7 0

Answer:

the answer you are looking for is <u>D </u>The number of calories in the packs of trail mix have a greater variation than the number of calories in the packs of crackers.

Step-by-step explanation:

mote1985 [20]3 years ago
6 0

Answer:D, “the number of calories...”

Step-by-step explanation:

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Harlamova29_29 [7]

Answer:

1. Callum = 2; Eilidh = 17; Caitlin's =22.

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Explanation:

Q1. Callum, Eilidh, and Caitlin

Let x = Callum's age

     y = Eilidh's age

     z = Caitlin's age

We have three conditions.

(1)  x = y - 5

(2) z = y + 15

(3) x + y + z = 31

Step 1. Eliminate one of the variables in two of the equations

Subtract (1) from (2):                      z - x = 20

Rearrange:                 (4)             -x + z = 20

Solve (2) for y:           (5)                     y = z - 15

Substitute into (3):         x +  z - 15  + z = 31

                                 (6) x + 2z             = 46

Step 2. Set up two new equations in two variables

(5)                          -x +   z = 20

(6)                           x + 2z = 46

Add (5) and (6):           3z = 66

Divide each side by 2: z = 22

Step 3. Substitute z into (5)

-x + 22 = 20

 x          = 2

Step 4. Substitute x into (1)

                                    2 = y - 5

Add 5 to each side     y = 7

Callum's age is 2; Eilidh's age is 7; Caitlin's age is 22.

Q2. Ewan and the tree

Let x = Ewan's age

      y = tree's age

We have two conditions.

                                     (1)          y = 7x

                                     (2)   x + y = 352

Rearrange (1)                (3) -7x + y =     0

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Subtract (3) from (2)          8x       = 352

Divide each side by 8         x       =    44

Substitute y into (1)                    y = 7 × 44

                                                  y =   308

Ewan's age is 44; the tree's age is 308.

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