Answer:
![w = 6](https://tex.z-dn.net/?f=%20w%20%3D%206%20)
Step-by-step explanation:
ST = w + 6,
PR = w
From the diagram given, we can deduce that PR is the midsegment of ∆QST. Therefore, according to the midsegment theorem:
PR = ½ of ST
Plug in the values into the equation and solve for w.
![w = \frac{1}{2}(w + 6)](https://tex.z-dn.net/?f=%20w%20%3D%20%5Cfrac%7B1%7D%7B2%7D%28w%20%2B%206%29%20)
(distributive property of equality)
(subtraction property of equality)
(multiplication property of equality)
![2w - 6 = w](https://tex.z-dn.net/?f=%202w%20-%206%20%3D%20w%20)
(subtraction property of equality)
![- 6 = - w](https://tex.z-dn.net/?f=%20-%206%20%3D%20-%20w%20)
Divide both sides by -1
![6 = w](https://tex.z-dn.net/?f=%206%20%3D%20w%20)
![w = 6](https://tex.z-dn.net/?f=%20w%20%3D%206%20)
5x + 13 Hope this helps you
Answer:
x = 88.2
Step-by-step explanation:
The angle at the top of the triangle = 90° - 10° = 80°
and the left side of the triangle is x ( opposite sides of a rectangle )
Using the tangent ratio in the right triangle
tan80° =
= ![\frac{500}{x}](https://tex.z-dn.net/?f=%5Cfrac%7B500%7D%7Bx%7D)
Multiply both sides by x
x × tan80° = 500 ( divide both sides by tan80° )
x =
≈ 88.2
Answer:
The total amount paid by Gabriel at the local gas station is $70.49.
Step-by-step explanation:
Cost of gasoline per gallon = $2.75
Cost of diesel per gallon = $3.02
Amount of gasoline Gabriel needs = 15.2 gallons
Amount of diesel Gabriel needs = 9.5 gallons
Compute the total amount paid by Gabriel at the local gas station as follows:
Total Cost = Cost of gasoline × Amount of gasoline
+ Cost of diesel × Amount of diesel
![=(2.75\times 15.2)+(3.02\times 9.5)\\\\=41.8+28.69\\\\=70.49](https://tex.z-dn.net/?f=%3D%282.75%5Ctimes%2015.2%29%2B%283.02%5Ctimes%209.5%29%5C%5C%5C%5C%3D41.8%2B28.69%5C%5C%5C%5C%3D70.49)
Thus, the total amount paid by Gabriel at the local gas station is $70.49.
Answer:
s. p = 270 Rs
discount = 10%
mp.= ?
Mp = s. p + discount
= 270 + 10/100*270
= 270 + 27
= 297 Rs
<h2>297 Rs is the marked price </h2>