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3 years ago

14

Last weekend, Charlie raked leaves in his front yard l. He noticed that 7/3 kilograms of leaves filled 4/9 of a bag. What is the

unit rate for kilograms of leaves per bag?

1 answer:

Archy [21]3 years ago

3 0

7kg:4/9 bag
?kg:1 bag

7÷4/9 or 7×9/4=63/4 or 15.75. As a result, the unit rate is 15.75 kg of leaves per bag. Hope it help!

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Given: <br> PQ<br> ⊥<br> QR<br> , PR=20,<br> SR=11, QS=5<br> Find: The value of PS.

dlinn [17]

Answer:

The value of the side PS is 26 approx.

Step-by-step explanation:

In this question we have two right triangles. Triangle PQR and Triangle PQS.

Where S is some point on the line segment QR.

Given:

PR = 20

SR = 11

QS = 5

We know that QR = QS + SR

QR = 11 + 5

QR = 16

Now triangle PQR has one unknown side PQ which in its base.

Finding PQ:

Using Pythagoras theorem for the right angled triangle PQR.

PR² = PQ² + QR²

PQ = √(PR² - QR²)

PQ = √(20²+16²)

PQ = √656

PQ = 4√41

Now for right angled triangle PQS, PS is unknown which is actually the hypotenuse of the right angled triangle.

Finding PS:

Using Pythagoras theorem, we have:

PS² = PQ² + QS²

PS² = 656 + 25

PS² = 681

PS = 26.09

PS = 26

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3 years ago

Multiply c^2(c^2-10c+25)

Artemon [7]

Step-by-step explanation:

c^2( c^2-10c+25)

=c^4 - 10c^3 + 25c^2

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3 years ago

12 + x/4 = 9<br> Simplify Plz need ASAP

agasfer [191]

Answer: X = -12

Step-by-step explanation: 1) 12 + x/4 = 9

2) 12 + x/ 2^2 = 9

3) x/ 2^2 + 12 = 9

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3 years ago

H.C.F of 672 and 120 is

Vlada [557]

Answer:

24

Step-by-step explanation:

Check attachment for explanation... hope it helps :)

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3 years ago

the volume of the a sphere whoes diameter is 18 cm is cubic cm . if it's diameter were reduced by half, it's volume would be of

FrozenT [24]

Answer:

The new volume is 8 times smaller than the original volume

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube

Let

z-----> the scale factor

x ----> the volume of the reduced sphere

y ----> the volume of the original sphere

so

$z^{3}=\frac{x}{y}$

we have

$z=1/2$ ----> scale factor

substitute

$(1/2)^{3}=\frac{x}{y}$

$(1/8)=\frac{x}{y}$

$x=\frac{y}{8}$

therefore

The new volume is 8 times smaller than the original volume

Verify

The volume of the original sphere is

$r=18/2=9\ cm$ ---> the radius is half the diameter

$V=\frac{4}{3}\pi (9)^{3}=972\pi \ cm^{3}$

the volume of the reduced sphere is

$r=9/2=4.5\ cm$ ---> the radius is half the diameter

$V=\frac{4}{3}\pi (4.5)^{3}=121.5\pi \ cm^{3}$

Divide the volumes

$972\pi \ cm^{3}/121.5\pi \ cm^{3}=8$

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3 years ago