Answer:
Ix = Iy =
Radius of gyration x = y = 
Step-by-step explanation:
Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.
Mass of disk = ρπR2
Moment of inertia about its perpendicular axis is
. Moment of inertia of quarter disk about its perpendicular is
.
Now using perpendicular axis theorem, Ix = Iy =
=
.
For Radius of gyration K, equate MK2 = MR2/16, K= R/4.
Answer:
X =3 and x =6
Step-by-step explanation:
Just look at the line where they cross another line,
The time it will take the principal to grow to the desired amount is 0.7 years
Using the compound interest formula :
A = P(1 + r/n)^(nt)
A = final amount = 225,000
P = principal = 180,000
r = rate = 3.12%
n = Number of compounding times per period = 12(monthly)
t = time
225000 = 180000(1 + (0.0312 /12))^(12t)
Divide both sides by 180000
225000/180000 = (1 + (0.0312 /12))^(12t)
1.25 = 1.026^12t
Take the log of both sides
0.0969100 = 0.0111473 × 12t
0.0969100 = 0.1337676t
Divide both sides by 0.1337676 to isolate t
0.0969100 / 0.1337676 = t
0.7244 years
0.7 years
It will take 0.7 years for the amount to grow
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Answer:
-0.2
Step-by-step explanation:
Answer:
4
Step-by-step explanation: