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4 years ago

Find the intersection of the following sets.

Mathematics

1 answer:

bija089 [108]4 years ago

3 0

Intersection means "AND" so whats in the first set AND in the second set. look for the numbers that are in both sets.

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Eight times a number increased by 6 is 62

N76 [4]

8x+6=62

8x=62-6

8x=56

X=56/8

X=7

The answer is 7. Hope this helps!

3 0

3 years ago

Read 2 more answers

Subtract. 5x^2-5x+1-(2x^2+9x-6)

Talja [164]

<h2>Hello!</h2>

The answer is:

$3x^{2} -14x+7$

To solve the problem we need to add/subtract like terms. We need to remember that like terms are the terms that share the same variable and the same exponent.

For example, we have:

$x^{2} +2x+3x=x^{2} +(2x+3x)=x^{2}+5x$

We have that we were able to add just the terms that were sharing the same variable and exponenr (x for this case).

So, we are given the expression:

$5x^2-5x+1-(2x^2+9x-6)=5x^{2}-2x^{2}-5x-9x+1-(-6)\\\\(5x^{2}-2x^{2})+(-5x-9x)+(1-(-6))=3x^{2}-14x+7$

Hence, the answer is:

$3x^{2} -14x+7$

Have a nice day!

4 0

3 years ago

86 is 45% of what number

Alik [6]

Hello there! We are talking about 86 being part of a number, so we are looking for the whole. To find the number we are looking for, we can write and solve a proportion. Set it up like this:

86/x = 45/100

86 is 45% of a number. We know the part, so now we are looking for the whole. 45% is part of 100%, so we put that part together. Cross multiply the digits. 100 * 86 is 8,600. 45 * x is 45x. That simplifies to 8,600 = 45x. Now, divide each side by 45 to isolate the x. 45x/45 cancels out. 8,600/45 is 191.1111111 or 191 1/9 in fraction form. There. x = 191 1/9 86 is 45% or 191 1/9

Note: Or, if you have to round to the nearest whole number, the answer is 191, or if you have to round to the nearest tenth, the answer is 191.1. It all depends on if the answer needs to be rounded or exact.

4 0

3 years ago

Write and equation for the shift of the parent graph y=1/x

SashulF [63]

You can think of this equation as $\bf f(x)=\cfrac{1}{x}\implies f(x)=(x)^{-1}$

and thus apply the transformations to it as such

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}\\\\
--------------------\\\\$

$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\$

$\bf \bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

1) D = 2, C = +3

2) D = -12, C = -2

3) C = +6, D = 3

4) C = -7, D = -7

7 0

3 years ago

Help please asap?!?!?!

Gwar [14]

In similar figures, the angle measures are the same but the side lengths are different. So in #4, x = 42. Since all the angles of a quadrilateral added up equal 360, then y is 360-90-90-42=138. For number 5, make sure you match up the sides correctly in your ratio: $\frac{2}{x}= \frac{4}{8}$ . You could cross multiply to get 4x=16, and x = 4, or you could just realize that reducing 4/8 will give you 2/4 and x = 4. Going back to the idea that in similar shapes corresponding angles are the same measure, x in #6 is 63

3 0

3 years ago