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3 years ago

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1. Eric has $115 to spend on back to school clothes. So far, he has spent $90. Write an inequality to show how much more money E

ric can spend.

1 answer:

xz_007 [3.2K]3 years ago

5 0

Eric can spent $29 for now

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Answer both for ( brain list, thanks, 5 star review)

morpeh [17]

2/12 1/12 i hope this is clear

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3 years ago

PLEASE HELP PLEASE WILL GIVE BRAINLIEST !!!!! Freya is training for a track race. She starts by sprinting 200 yards. She gradual

DedPeter [7]

Answer:

A. $a_n=200+(n-1)5$

Step-by-step explanation:

Given,

The initial sprinting of Freya = 200 yards,

Also, She gradually increases her distance by 5 yards per day,

So, in second day her sprinting = 200 + 5 = 205 yards,

In third day = 205 + 5 = 210 yards,

In fourth day = 210 + 5 = 215 yards,

...................., so on,.....

Hence, the sequence that shows the given situation,

200, 205, 210, 215, .........

Which is an A.P.

That having first term, a = 200,

Common difference, d = 5,

Thus, the explicit formula for the given situation is,

$a_n=a+(n-1)d$

$\implies a_n=200+(n-1)5$

Option A is correct.

7 0

4 years ago

Read 2 more answers

Hi guys I can't seem to figure out the period of this graph. Can someone help me!

DENIUS [597]

Answer:

3b

Step-by-step explanation:

The period of the sine curve is the length of one cycle of the curve. The curve take 3b before repeating itself.

4 0

4 years ago

allochka39001 [22]

Answer:

164

Step-by-step explanation:

You split figures into 2 separate rectangles

one will be 3cm to 22-14=8cm

another one will be 14cm to 10

So, you get separate areas and sum them

8*3=24

14*10=140

24+ 140= 164

4 0

3 years ago

The countries population in 1991 was 231 million . In 1999 it’s was 233 million. estimate the population in 2003 used The expone

liraira [26]

Answer:

The population in 2003 was 234 million

Step-by-step explanation:

In order to calculate the population in 2003 we would have to use the The exponential growth formula as follows:

p(y)=ir^t

According to the given data:

p(y)=233 million

i=231 million

t =1999-1991

Therefore, 233 million=231 million r^(1999-1991)

(233 million/231 million)^(1/8)=r

p(y)=231 million(233 million/231 million)^((y-1991)/8)

Therefore, in 2003 p(2003)=231 million(233 million/231 million)^((2003-1991)/8)

p(2003)=231 million(233 million/231 million)^(1.5)

p(2003)=234 million

The population in 2003 was 234 million

7 0

4 years ago