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Tanya [424]
3 years ago
12

If P(A)=2/3, P(B)=4/5, and P(A U B) =11/15, what is P(A ∩ B)?

Mathematics
2 answers:
Evgen [1.6K]3 years ago
7 0

Answer:

P(A ∩ B) = \frac{11}{15}

Step-by-step explanation:

If P(A)=2/3, P(B)=4/5, and P(A U B) =11/15

we need to find out  P(A ∩ B)

P(A U B) = P(A) + P(B) - P(A ∩ B)

Now we add P(A ∩ B) on both sides and subtract P(A U B) from both sides

P(A ∩ B) = P(A) + P(B)- P(A U B)

now we plug in the values

P(A ∩ B) = \frac{2}{3} + \frac{4}{5} - \frac{11}{15}

Make the denominators same . LCD  is 15

P(A ∩ B) = \frac{10}{15} + \frac{12}{15} - \frac{11}{15}

P(A ∩ B) = \frac{22}{15}-\frac{11}{15}

P(A ∩ B) = \frac{11}{15}

Juliette [100K]3 years ago
3 0
The answer is A on apex 
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Answer:

The quadratic equation used to determine the thickness of frame is \left(3+2x\right)\times \left(2+2x\right)=7

Step-by-step explanation:

Refer to the attachment for the diagram.

Consider EFGH as the the frame and ABCD as the mirror which is to be hanged.

Let me the "x" be the thickness of the frame as shown in diagram.

Given that, BC = 3 ft and DC = 2 ft which is the dimensions of the mirror.

Now to calculate the length and width of the frame consider following calculation,

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Width of frame HG = x + 2 + x  

Width of frame HG =  2 + 2x  

2x is the addition of the thickness which is present on both side of mirror

Length of frame FG = x + BC + x

Length of frame FG = x + 3 + x

Length of frame FG = 3 + 2x

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Given that area of frame is 7\:ft^{2}

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