Answer:
cos = adjacent/hypotenuse
3/square root13
now you do square root 13 x3 divided by square root 13^2
= 3square root13/13
hope that answers your question
Answer:
The scale of the copy of the ticket is 
Step-by-step explanation:
we know that
To find the scale divide the long of the copy of a ticket by the long of the original of a ticket
so
identity used is
x³ + y³+ z³– 3xyz = (x + y + z) (x² + y² + z² – xy – yz – zx).
then use
(x+y+z)² = x²+y²+z²+2(xy+yz+xz)
225= 83 + 2(xy+yz+xz)
xy+yz+xz = (225-83)/2
xy+yz+xz= 142/2
xy+yz+xz= 71
ok
now use identity
x³ + y³+ z³– 3xyz = (x + y + z) (x² + y² + z² – xy – yz – zx).
now
x³ + y³+ z³– 3xyz = 15 (83 – xy – yz – zx).
= 15[83 - (71)]
= 15×12
=180
23 is the minimum because 155 does not go into evenly and you have to have enough room for everybody, and make sure not to leave anybody out. 155 divided by 7 is 22.1428571429, you have to round it up to 23 so that everybody has a seat. Hope it helps!!
